Matlab基本操作

1.随机产生一个10×10的矩阵，矩阵元素为0～10之间的数；对每列求均值产生一个均值行向量；求矩阵的秩，判断是否为可逆阵，在可逆的情况下求解逆矩阵，并验证逆矩阵的正确性，即判断两个矩阵的乘积是否为单位阵。

clear all;
close all;
A = rand(10,10)*10
B = inv(A)
disp('The A*B equals to :');
disp(A*B);
fprintf('sure det(A * B) == %f',det(A*B));
C = det(A*B)

2. 将表达式((x-4)(x+5)(x^2-6x+9))展开为多项式形式，并求其对应的一元n次方程的根。

clear all;
close all;
 
a = [1 -6 9];
b = [0 1 5];
c = [0 1 -4];
d = conv(conv(a,b),c)
disp('The roots is :');
AN = roots(d);
len = length(AN);
for i = 1:len
    fprintf('X%d = %3f
',i,AN(i));
end

3. 将有理分式进行部分分式展开:(H(s) = displaystylefrac{2s^2+2s+13}{(s+1)(s-2)(s-3)})

clear all;
close all;
 
n = [2 2 13];
p1 = [0 1 1];
p2 = [0 1 -2];
p3 = [0 1 -3];
r = [-1 2 3];
 
p = poly(r)

[above,below,mul] = residue(n,p)

4. 利用符号函数绘制信号(f_1(t)=displaystylefrac{sin(omega_0(t-t_0))}{omega_0t}), (f_2(t) = displaystylefrac{sinomega_0(t-t_0)}{omega_0(t-t_0)}),(f(t) = f_1(t)+f_2(t))

OmigaSet = [2:3:15];
t = sym('t');
Omiga = sym('Omiga');
 
f1 = sym('sin(Omiga*t)/(Omiga*t)');
f2 = sym('sin(Omiga*(t-3))/(Omiga*(t-3))');
 
for i = 1:length(OmigaSet)
    
    Plotf1 = subs(f1,Omiga,OmigaSet(i));
    Plotf2 = subs(f2,Omiga,OmigaSet(i));
    
    subplot(2,2,1),h1 = ezplot(Plotf1);
    xlim([-3,7]);
    ylim([-.5,1.5]);
    subplot(2,2,2),h2 = ezplot(Plotf2);
    xlim([-3,7]);
    ylim([-.5,1.5]);
    subplot(2,2,[3 4]),h3 = ezplot(Plotf1 + Plotf2);
    xlim([-3,7]);
    ylim([-.5,1.5]);
    set([h1,h2,h3],'LineWidth',1);
    title('Superposition Of two figure above');
    scrsz = get(0,'ScreenSize');
    set(gcf,'Position',scrsz);
    saveas(gcf,['Item2_4_' num2str(i) '.png']);
end