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  • leetcode——Search for a Range 排序数组中寻找目标下标范围(AC)

    Given a sorted array of integers, find the starting and ending position of a given target value.

    Your algorithm's runtime complexity must be in the order of O(log n).

    If the target is not found in the array, return [-1, -1].

    For example,
    Given [5, 7, 7, 8, 8, 10] and target value 8,
    return [3, 4].

    class Solution {
    public:
        vector<int> searchRange(int A[], int n, int target) {
            assert(A!=NULL && n!=0);
            vector<int> result;
            int start = 0, end = n-1, mid;
            while(start <= end)
            {
                mid = (start+end)/2;
                if(A[mid] == target)
                {
                    while(mid>=0 && A[mid]==target)
                        mid--;
                    result.push_back(++mid);
                    while(mid<=n-1 && A[mid]==target)
                        mid++;
                    result.push_back(--mid);
                    return result;
                }
                else if(A[mid] < target)
                    start = mid+1;
                else
                    end = mid-1;
            }
            result.push_back(-1);
            result.push_back(-1);
            return result;
        }
    };


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  • 原文地址:https://www.cnblogs.com/ldxsuanfa/p/10730202.html
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