起因
今天在写东西的时候,用到了多线程。遇到了个问题:
子线程的异常,在父线程中无法捕获。
解决
问题代码
问题代码示例代码如下:
import threading class SampleThread(threading.Thread): def run(self): raise Exception('An error occured here.') def main(): try: thread_obj = SampleThread() thread_obj.start() except Exception: print 'catch that' if __name__ == '__main__': main()
运行结果如下:
Exception in thread Thread-1: Traceback (most recent call last): File "E:installDevelopDirectorypy27lib hreading.py", line 801, in __bootstrap_inner self.run() File "E:/program/ljt_test/test/test_process.py", line 51, in run raise Exception('An error occured here.') Exception: An error occured here.
解决办法
通过查看资料:http://stackoverflow.com/questions/2829329/catch-a-threads-exception-in-the-caller-thread-in-python
出现上述问题是因为:执行到 thread_obj.start()
时,父线程就会立即返回结果。然后,生成的子线程在自己独立的上下文中执行,并使用自己的堆栈。子线程发生的任何异常都是在子线程的上下文中,并且它在它自己的堆栈中(独立于父线程)。
所以,解决办法是:将这些信息传递给父线程。代码如下:
#coding=utf-8 import threading import Queue import sys class ExcThread(threading.Thread): def __init__(self, bucket): super(ExcThread, self).__init__() self.bucket = bucket def run(self): try: raise Exception('An error occured here.') # pass except Exception: # 异常信息元祖放入队列传递给父进程 self.bucket.put(sys.exc_info()) def main(): bucket = Queue.Queue() thread_obj = ExcThread(bucket) thread_obj.start() # 循环获取子线程的异常信息 while 1: try: exc = bucket.get(block=False) except Queue.Empty:#系统已经定义了,可以直接用 pass else: exc_type, exc_obj, exc_trace = exc # deal with the exception print exc_type, exc_obj print exc_trace # 防止阻塞 thread_obj.join(0.1) if thread_obj.isAlive(): continue else: break if __name__ == '__main__': main()
Queue文件中定义的: