a letter and a number

a letter and a number

时间限制：3000 ms  |  内存限制：65535 KB

难度：1

 

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

上传者

苗栋栋

 

01.#include<stdio.h>

02.int main()

03.{

04.int i,N,k,a[10001]={0},b[10001]={0};

05.scanf("%d",&N);

06.getchar();

07.for(i=0;i<N;i++)

08.{

09.scanf("%c%d",&a[i],&b[i]);

10.getchar();

11.}

12. 

13.for(i=0;i<N;i++)

14.{

15.if(a[i]>=97)

16.a[i]=96-a[i];

17.else

18.a[i]=a[i]-64;

19.printf("%d ",a[i]+b[i]);

20.}

21.return 0;

22. 

23.}