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  • POJ1163The Triangle

    The Triangle
    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 30728   Accepted: 18184

    Description

    7
    3   8
    8   1   0
    2   7   4   4
    4   5   2   6   5
    
    (Figure 1)
    Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right. 

    Input

    Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99.

    Output

    Your program is to write to standard output. The highest sum is written as an integer.

    Sample Input

    5
    7
    3 8
    8 1 0 
    2 7 4 4
    4 5 2 6 5

    Sample Output

    30
    记忆化搜索,hash数组记录当前最大值
    对于3176,挂了,看来还是有问题
    #include <iostream>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    
    int maps[105][105];
    int Hash[105][105];
    int n;
    
    void DFS(int x, int y)
    {
    	if(x==n) return;
    	for(int i=0;i<=1;i++)
    	{
    		int p = x + 1;
    		int q = y + i;
    		if(maps[p][q] + Hash[x][y] > Hash[p][q])
    		{
    			Hash[p][q] = maps[p][q] + Hash[x][y];
    			DFS(p,q);
    		}
    	}
    }
    
    int main()
    {
    	freopen("in.txt","r",stdin);
    	cin>>n;
    	memset(Hash,0,sizeof(Hash));
    	memset(maps,0,sizeof(maps));
    	for(int i=1;i<=n;i++)
    	{
    		for(int j=1;j<=i;j++)
    		{
    			cin>>maps[i][j];
    		}
    	}
    	Hash[1][1] = maps[1][1];
    	DFS(1,1);
    	int sum = -1;
    	for(int i=1;i<=n;i++)
    	{
    		for(int j=1;j<=i;j++)
    		{
    			sum = max(sum,Hash[i][j]);
    		}
    	}
    	cout<<sum<<endl;
    }


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  • 原文地址:https://www.cnblogs.com/lgh1992314/p/5835314.html
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