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  • java代码实现ZIP格式解压

    二话不说,代码奉上:

      1 import java.io.*;
      2 import java.util.*;
      3 import org.apache.tools.zip.*;
      4 
      5 public class AdapterZipFile {
      6     String zipFileName = null;//zip文件的绝对路径
      7     String outputDirectory =null;//zip文件解压缩后的存放路径
      8     ArrayList list = new ArrayList();//文件解压缩后的文件列表绝对路径
      9 
     10 //    public AdapterZipFile(String zipFileName) {
     11 //        if(zipFileName == null){
     12 //            return;
     13 //        }
     14 //        this.zipFileName = zipFileName.replace("/","\\");
     15 //        unZipFile();
     16 //    }
     17 
     18     //初始化
     19     public AdapterZipFile(String zipFileName, String outputDirectory){  //可以实现压缩文件中包含子文件夹的情况
     20         if(zipFileName == null){
     21             return;
     22         }
     23         this.zipFileName = zipFileName;
     24         if(outputDirectory != null){
     25              this.outputDirectory = outputDirectory;
     26         }else{
     27             this.outputDirectory = zipFileName.substring(0,
     28                     zipFileName.replace('\\', '/').lastIndexOf("/"));
     29         }
     30        // unZipFile();
     31     }
     32 
     33    //创建目录
     34     private void createDirectory(String directory, String subDirectory) {
     35         String dir[];
     36         File fl = new File(directory);
     37         try {
     38             if (subDirectory == "" && fl.exists() != true)
     39                 fl.mkdirs();
     40             else if (subDirectory != "") {
     41                 dir = subDirectory.replace("\\","/").split("/");
     42                 for (int i = 0; i < dir.length; i++) {
     43                     File subFile = new File(directory + File.separator + dir[i]);
     44                     if (!subFile.exists())
     45                         subFile.mkdir();
     46                     directory += File.separator + dir[i];
     47                 }
     48             }
     49         }catch (Exception ex) {
     50             System.out.println(ex.getMessage());
     51         }
     52     }
     53 
     54     //解压缩文件
     55     //如果outputDierctory为null,解压到zipFileName文件的当前目录下
     56     public void unZipFile() {
     57         File file = new File(zipFileName);
     58         if (!file.exists()) {
     59             return;
     60         }
     61         createDirectory(outputDirectory, "");
     62 
     63         try {
     64             ZipFile zipFile = new ZipFile(zipFileName);
     65             Enumeration e = zipFile.getEntries();
     66             ZipEntry zipEntry = null;
     67             while (e.hasMoreElements()) {
     68                 zipEntry = (ZipEntry) e.nextElement();
     69                 if (zipEntry.isDirectory()) {
     70                     String name = zipEntry.getName();
     71                     name = name.substring(0, name.length() - 1);
     72                     File f = new File(outputDirectory + File.separator + name);
     73                     f.mkdir();
     74                 } else {
     75                     String fileName = zipEntry.getName();
     76                     fileName = fileName.replace('\\', '/');
     77                     //文件在多层目录下 这时需要创建目录如:d1/d2/1.txt
     78                     if (fileName.indexOf("/") != -1) {
     79                         createDirectory(outputDirectory, fileName.substring(0,
     80                                 fileName.lastIndexOf("/")));
     81                         fileName = fileName.substring(
     82                                 fileName.lastIndexOf("/") + 1, fileName
     83                                 .length());
     84                     }
     85 
     86                     list.add(outputDirectory + File.separator
     87                                       + zipEntry.getName());
     88                     File f = new File(outputDirectory + File.separator
     89                                       + zipEntry.getName());
     90 
     91                     f.createNewFile();
     92                     InputStream in = zipFile.getInputStream(zipEntry);
     93                     FileOutputStream out = new FileOutputStream(f);
     94 
     95                     byte[] by = new byte[1024*1024*6];
     96                     int c;
     97                     while ((c = in.read(by)) != -1) {
     98                         out.write(by, 0, c);
     99                     }
    100                     out.close();
    101                     in.close();
    102                 }
    103             }
    104         } catch (Exception ex) {
    105             System.out.println(ex.getMessage());
    106         }
    107     }
    108 
    109    //返回zip文件解压撒后文件列表的绝对路径
    110     public ArrayList GetZipFileList(){
    111         return list;
    112     }
    113     public static void main(String[] args) {
    114          AdapterZipFile uzip=new AdapterZipFile("F:/lucene视频和示例.zip","F:/2013");
    115          long a=System.currentTimeMillis();
    116          uzip.unZipFile();
    117          long b=System.currentTimeMillis();
    118          System.out.println("文件解压耗时"+(b-a) +"毫秒");
    119     }
    120 }

    解压可以根据目标文件的大小,适时的调整缓存流的大小。刚刚测试了下把缓存流设置在1024还是最佳的,解压900MB左右的ZIP文件大概需要22S左右,当然这可能和你自己所用的电脑有一点关系,但是我自己也用了解压软件测试了下,大概在10s左右,这说明上面的代码还是有很大优化的空间的,希望看到这篇博文的同学,可以和我交流下!!!!!一起学习,一起进步!@!!!!

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  • 原文地址:https://www.cnblogs.com/liangdelin/p/2779462.html
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