zoukankan      html  css  js  c++  java
  • LeetCode-Design Hit Counter

    Design a hit counter which counts the number of hits received in the past 5 minutes.

    Each function accepts a timestamp parameter (in seconds granularity) and you may assume that calls are being made to the system in chronological order (ie, the timestamp is monotonically increasing). You may assume that the earliest timestamp starts at 1.

    It is possible that several hits arrive roughly at the same time.

    Example:

    HitCounter counter = new HitCounter();
    
    // hit at timestamp 1.
    counter.hit(1);
    
    // hit at timestamp 2.
    counter.hit(2);
    
    // hit at timestamp 3.
    counter.hit(3);
    
    // get hits at timestamp 4, should return 3.
    counter.getHits(4);
    
    // hit at timestamp 300.
    counter.hit(300);
    
    // get hits at timestamp 300, should return 4.
    counter.getHits(300);
    
    // get hits at timestamp 301, should return 3.
    counter.getHits(301); 
    

    Follow up:
    What if the number of hits per second could be very large? Does your design scale?

    Credits:
    Special thanks to @elmirap for adding this problem and creating all test cases.

    Analysis:

    Since only recording 300 second, we can directly use CircularBuffer.

    Solution:

     1 public class HitCounter {
     2         /** Initialize your data structure here. */
     3         public HitCounter() {
     4             hit = new int[300];
     5             head = hit.length - 1;
     6             lastCallTime = 0;
     7             totalHits = 0;
     8         }
     9 
    10         public void advanceTime(int timestamp) {
    11             int duration = timestamp - lastCallTime;
    12             lastCallTime = timestamp;
    13             
    14             if (duration>=300){
    15                 Arrays.fill(hit,0);
    16                 totalHits = 0;
    17                 head = (head+duration) % hit.length;
    18                 
    19                 return;
    20             }
    21             
    22             for (int i = 0; i < duration; i++) {
    23                 head = (head + 1) % hit.length;
    24                 totalHits -= hit[head];
    25                 hit[head] = 0;
    26             }
    27         }
    28 
    29         /**
    30          * Record a hit.
    31          * 
    32          * @param timestamp
    33          *            - The current timestamp (in seconds granularity).
    34          */
    35         public void hit(int timestamp) {
    36             advanceTime(timestamp);
    37             hit[head]++;
    38             totalHits++;
    39         }
    40 
    41         /**
    42          * Return the number of hits in the past 5 minutes.
    43          * 
    44          * @param timestamp
    45          *            - The current timestamp (in seconds granularity).
    46          */
    47         public int getHits(int timestamp) {
    48             advanceTime(timestamp);
    49             return totalHits;
    50         }
    51 
    52         int[] hit;
    53         int head;
    54         int lastCallTime;
    55         int totalHits;
    56 }
    57 
    58 /**
    59  * Your HitCounter object will be instantiated and called as such:
    60  * HitCounter obj = new HitCounter();
    61  * obj.hit(timestamp);
    62  * int param_2 = obj.getHits(timestamp);
    63  */
  • 相关阅读:
    在MS Sql Server中可以能过以下的方法查询出磁盘空间的使用情况及各数据库数据文件及日志文件的大小及使用利用率:
    sqlserver日志的备份与还原
    C#中String 与Color之间的相互转换
    sql 替换字符串
    Components_Box
    射线检测与碰撞通道设置
    切碎方块
    音乐可视化
    枚举
    UI与Actor(蓝图)的互动
  • 原文地址:https://www.cnblogs.com/lishiblog/p/5691644.html
Copyright © 2011-2022 走看看