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  • LeetCode-Range Addition

    Assume you have an array of length n initialized with all 0's and are given k update operations.

    Each operation is represented as a triplet: [startIndex, endIndex, inc] which increments each element of subarray A[startIndex ... endIndex] (startIndex and endIndex inclusive) with inc.

    Return the modified array after all k operations were executed.

    Example:

    Given:
    
        length = 5,
        updates = [
            [1,  3,  2],
            [2,  4,  3],
            [0,  2, -2]
        ]
    
    Output:
    
        [-2, 0, 3, 5, 3]
    

    Explanation:

    Initial state:
    [ 0, 0, 0, 0, 0 ]
    
    After applying operation [1, 3, 2]:
    [ 0, 2, 2, 2, 0 ]
    
    After applying operation [2, 4, 3]:
    [ 0, 2, 5, 5, 3 ]
    
    After applying operation [0, 2, -2]:
    [-2, 0, 3, 5, 3 ]
    
    Solution:

     1 public class Solution {
     2     public int[] getModifiedArray(int length, int[][] updates) {
     3         int[] res = new int[length];
     4         Arrays.fill(res,0);
     5         for (int[] update : updates){
     6             int start = update[0];
     7             int end = update[1]+1;
     8             int val = update[2];
     9 
    10             res[start] += val;
    11             if (end<length){
    12                 res[end] -= val;
    13             }
    14         }
    15 
    16         int sum = 0;
    17         for (int i=0;i<length;i++){
    18             sum += res[i];
    19             res[i] = sum;
    20         }
    21         return res;
    22     }
    23 }
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  • 原文地址:https://www.cnblogs.com/lishiblog/p/5691683.html
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