A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
- Both the left and right subtrees must also be binary search trees.
A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.
Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.
Output Specification:
For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.
Sample Input:
10
1 2 3 4 5 6 7 8 9 0
Sample Output:
6 3 8 1 5 7 9 0 2 4
已知一组数据,我们需要进行构成满二叉排序树,并且打印层序遍历。
我们可以进行sort一下,就是中序遍历,然后进行中序遍历插入数据即可。
#include <iostream> #include <vector> #include <algorithm> using namespace std; int N, index_v = 0 ; vector<int> v, res; void inorder(int index_res){ if(index_res >= N) return ; inorder(2 * index_res + 1); res[index_res] = v[index_v++]; inorder(2 * index_res + 2); } int main(){ cin >> N; v.resize(N); res.resize(N); for(int i = 0; i < N; i++) cin >> v[i]; sort(v.begin(),v.end()); inorder(0); cout << res[0]; for(int i = 1; i < N; i++) cout << " " << res[i]; system("pause"); return 0; }