zoukankan      html  css  js  c++  java
  • 1145 Hashing

    The task of this problem is simple: insert a sequence of distinct positive integers into a hash table first. Then try to find another sequence of integer keys from the table and output the average search time (the number of comparisons made to find whether or not the key is in the table). The hash function is defined to be ( where TSize is the maximum size of the hash table. Quadratic probing (with positive increments only) is used to solve the collisions.

    Note that the table size is better to be prime. If the maximum size given by the user is not prime, you must re-define the table size to be the smallest prime number which is larger than the size given by the user.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains 3 positive numbers: MSize, N, and M, which are the user-defined table size, the number of input numbers, and the number of keys to be found, respectively. All the three numbers are no more than 1. Then N distinct positive integers are given in the next line, followed by M positive integer keys in the next line. All the numbers in a line are separated by a space and are no more than 1.

    Output Specification:

    For each test case, in case it is impossible to insert some number, print in a line X cannot be inserted. where X is the input number. Finally print in a line the average search time for all the M keys, accurate up to 1 decimal place.

    Sample Input:

    4 5 4
    10 6 4 15 11
    11 4 15 2
    
     

    Sample Output:

    15 cannot be inserted.
    2.8

    哈希-平均搜索时间,我们将给定元素按照平方探测法进行插入,我们要求求出平均搜索时间。

    #include <iostream>
    #include <vector>
    using namespace std;
    bool isPrime(int N) {
        if(N <= 1) return false;
        for(int i = 2; i * i <= N; i++)
            if(N % i == 0) return false;
        return true;
    }
    int main() {
        int MSize, N, M, tmp;
        cin >> MSize >> N >> M;
        while(!isPrime(MSize)) MSize++;
        vector<int> hash(MSize, 0);
        while(N--) {
            cin >> tmp;
            int flag = true;
            for(int i = 0; i < MSize; i++) {
                if(hash[(tmp + i * i) % MSize] == 0) {
                    hash[(tmp + i * i) % MSize] = tmp;
                    flag = false;
                    break;
                }
            }
            if(flag) printf("%d cannot be inserted.
    ", tmp);
        }
        int cnt = 0;
        for(int c = 0; c < M; c++) {
            cin >> tmp;
            for(int i = 0; i <= MSize; i++) {
                cnt++;
                if(hash[(tmp + i * i) % MSize] == tmp ||
                    hash[(tmp + i * i) % MSize] == 0) 
                    break;
            }
        }
        printf("%.1lf", (double)cnt / M);
        return 0;
    }
  • 相关阅读:
    ssh端口转发
    linux git命令安装
    linux git命令
    linux cpio命令
    linux 抓包工具
    js 深拷贝 ,浅拷贝
    vue $router 打开新窗口
    excel常用操作
    Kafka Topic的增删改查操作
    linux上删除文件名乱码的文件
  • 原文地址:https://www.cnblogs.com/littlepage/p/12818000.html
Copyright © 2011-2022 走看看