R语言中aggregate函数
1、测试数据1
name <- LETTERS[1:8]
gender <- c("M","F","F","M","F","M","M","F")
age <- c(30,20,40,40,30,20,30,20)
height <- c(100,200,300,200,400,500,100,600)
a <- data.frame(name,gender,age,height)
a
2、测试2
a
b <- aggregate(a[,3:4], by=list(gender=gender), FUN=mean)
b
3、测试3
c <- aggregate(a[,3:4], by=list(gender=gender), FUN=sum)
c
4、测试4
a
d <- aggregate(a[,4], by=list(age=age),FUN=mean)
d
5、测试5
a
e <- aggregate(a[,4],by=list(gender=gender,age=age), FUN=mean)
e
f <- aggregate(a[,4],by=list(gender=gender,age=age), FUN=sum)
f