http://acm.hdu.edu.cn/showproblem.php?pid=4312
和 4311 的区别在于一个转换 自己还真想不出来
max(|x|,|y|) 等于 max(|x-y|,|x+y|)/2
原来的两点 (x1,y1) (x2,y2) 转换为 (x1-y1,x1+y1) (x2-y2,x2+y2)
最后记得除以2
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<map>
#include<queue>
#include<cmath>
#define LL long long
using namespace std;
const int N=100005;
struct node
{
int I;
LL x,y;
}mem[N];
LL l[N];
LL sumx[N];
LL sumy[N];
bool cmp1(node a,node b)
{
return a.x<b.x;
}
bool cmp2(node a,node b)
{
return a.y<b.y;
}
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
int n;
scanf("%d",&n);
for(int i=1;i<=n;++i)
{
LL x,y;
cin>>x>>y;
mem[i].x=x-y;
mem[i].y=x+y;
mem[i].I=i;
}
sort(mem+1,mem+n+1,cmp1);
l[0]=0;
for(int i=1;i<=n;++i)
{
l[i]=l[i-1]+mem[i].x;
}
for(int i=1;i<=n;++i)
{
sumx[mem[i].I]=((i-1)*mem[i].x-l[i-1])+((l[n]-l[i])-(n-i)*mem[i].x);
}
sort(mem+1,mem+n+1,cmp2);
l[0]=0;
for(int i=1;i<=n;++i)
{
l[i]=l[i-1]+mem[i].y;
}
for(int i=1;i<=n;++i)
{
sumy[mem[i].I]=((i-1)*mem[i].y-l[i-1])+((l[n]-l[i])-(n-i)*mem[i].y);
}
LL ans=sumx[1]+sumy[1];
for(int i=2;i<=n;++i)
{
if(sumx[i]+sumy[i]<ans)
ans=sumx[i]+sumy[i];
}
cout<<(ans/2)<<endl;
}
return 0;
}