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  • oracle 行转列问题

     1 select id,
     2        name, 
     3        sum(decode(tag_name, 'AAA', nvl(value, 0),'BBB' ,nvl(value, 0),0)) "imp_value",
     4        sum(decode(tag_name, 'C01', nvl(value, 0),'D01', nvl(value, 0), 0)) "click_value"
     5 
     6   from (SELECT a.id, a.name, d.tag_name, d.value
     7           FROM A a
     8           LEFT JOIN B b
     9             ON a.id = b.id
    10           left join d d
    11             on b.imp_url = d.tag_name
    12         union
    13         SELECT a.id, a.name, d.tag_name, d.value
    14           FROM A a
    15           LEFT JOIN C c
    16             ON a.id = c.id
    17           left join d d
    18             on c.click_url = d.tag_name) m
    19  group by id, name
    View Code

    下面是根据id和name 将value合并成一列

     1 select id,
     2        name,
     3        to_char(WMSYS.WM_CONCAT(tag_name)) tag_name,
     4        to_char(WMSYS.WM_CONCAT(value)) value
     5   from (SELECT a.id, a.name, d.tag_name, d.value
     6           FROM A a
     7           LEFT JOIN B b
     8             ON a.id = b.id
     9           left join d d
    10             on b.imp_url = d.tag_name
    11         union
    12         SELECT a.id, a.name, d.tag_name, d.value
    13           FROM A a
    14           LEFT JOIN C c
    15             ON a.id = c.id
    16           left join d d
    17             on c.click_url = d.tag_name) m
    18  group by id, name
    View Code


     

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  • 原文地址:https://www.cnblogs.com/liutoutou/p/3385380.html
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