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  • Java实现二叉树的前序、中序、后序、层序遍历(非递归方法)

      在上一篇博客中,实现了Java中二叉树的四种遍历方式的递归实现,接下来,在此实现Java中非递归实现二叉树的前序、中序、后序、层序遍历,在非递归实现中,借助了栈来帮助实现遍历。前序和中序比较类似,也简单一些,但是后序遍历需要两个栈来进行辅助,稍微复杂一些,层序遍历中借助了一个队列来进行实现。

    二叉树

      同样是那棵二叉树

    • 前序遍历:4 2 1 3 6 5 7 8 10

    • 中序遍历:1 2 3 4 5 6 7 8 10

    • 后序遍历:1 3 2 5 10 8 7 6 4

    • 层序遍历:4 2 6 1 3 5 7 8 10

    import java.util.LinkedList;
    import java.util.Queue;
    import java.util.Stack;
    
    public class Tree<AnyType extends Comparable<? super AnyType>>
    {
        private static class BinaryNode<AnyType>
        {
            BinaryNode(AnyType theElement)
            {
                this(theElement, null, null);
            }
    
            BinaryNode(AnyType theElement, BinaryNode<AnyType> lt, BinaryNode<AnyType> rt)
            {
                element = theElement;
                left = lt;
                right = rt;
            }
    
            AnyType element;
            BinaryNode<AnyType> left;
            BinaryNode<AnyType> right;
        }
    
        private BinaryNode<AnyType> root;
    
        public void insert(AnyType x)
        {
            root = insert(x, root);
        }
    
        public boolean isEmpty()
        {
            return root == null;
        }
    
        private BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> t)
        {
            if(t == null)
            {
                return new BinaryNode<>(x, null, null);
            }
    
            int compareResult = x.compareTo(t.element);
    
            if(compareResult < 0)
            {
                t.left = insert(x, t.left);
            }
            else if(compareResult > 0)
            {
                t.right = insert(x, t.right);
            }
            else
            {
                ;
            }
    
            return t;
        }
    
        /**
         * 前序遍历
         * 递归
         */
        public void preOrder(BinaryNode<AnyType> Node)
        {
            if (Node != null)
            {
                System.out.print(Node.element + " ");
                preOrder(Node.left);
                preOrder(Node.right);
            }
        }
    
        /**
         * 中序遍历
         * 递归
         */
        public void midOrder(BinaryNode<AnyType> Node)
        {
            if (Node != null)
            {
                midOrder(Node.left);
                System.out.print(Node.element + " ");
                midOrder(Node.right);
            }
        }
    
        /**
         * 后序遍历
         * 递归
         */
        public void posOrder(BinaryNode<AnyType> Node)
        {
            if (Node != null)
            {
                posOrder(Node.left);
                posOrder(Node.right);
                System.out.print(Node.element + " ");
            }
        }
    
        /*
         * 层序遍历
         * 递归
         */
        public void levelOrder(BinaryNode<AnyType> Node) {
            if (Node == null) {
                return;
            }
    
            int depth = depth(Node);
    
            for (int i = 1; i <= depth; i++) {
                levelOrder(Node, i);
            }
        }
    
        private void levelOrder(BinaryNode<AnyType> Node, int level) {
            if (Node == null || level < 1) {
                return;
            }
    
            if (level == 1) {
                System.out.print(Node.element + "  ");
                return;
            }
    
            // 左子树
            levelOrder(Node.left, level - 1);
    
            // 右子树
            levelOrder(Node.right, level - 1);
        }
    
        public int depth(BinaryNode<AnyType> Node) {
            if (Node == null) {
                return 0;
            }
    
            int l = depth(Node.left);
            int r = depth(Node.right);
            if (l > r) {
                return l + 1;
            } else {
                return r + 1;
            }
        }
    
        /**
         * 前序遍历
         * 非递归
         */
        public void preOrder1(BinaryNode<AnyType> Node)
        {
            Stack<BinaryNode> stack = new Stack<>();
            while(Node != null || !stack.empty())
            {
                while(Node != null)
                {
                    System.out.print(Node.element + "   ");
                    stack.push(Node);
                    Node = Node.left;
                }
                if(!stack.empty())
                {
                    Node = stack.pop();
                    Node = Node.right;
                }
            }
        }
    
        /**
         * 中序遍历
         * 非递归
         */
        public void midOrder1(BinaryNode<AnyType> Node)
        {
            Stack<BinaryNode> stack = new Stack<>();
            while(Node != null || !stack.empty())
            {
                while (Node != null)
                {
                    stack.push(Node);
                    Node = Node.left;
                }
                if(!stack.empty())
                {
                    Node = stack.pop();
                    System.out.print(Node.element + "   ");
                    Node = Node.right;
                }
            }
        }
    
        /**
         * 后序遍历
         * 非递归
         */
        public void posOrder1(BinaryNode<AnyType> Node)
        {
            Stack<BinaryNode> stack1 = new Stack<>();
            Stack<Integer> stack2 = new Stack<>();
            int i = 1;
            while(Node != null || !stack1.empty())
            {
                while (Node != null)
                {
                    stack1.push(Node);
                    stack2.push(0);
                    Node = Node.left;
                }
    
                while(!stack1.empty() && stack2.peek() == i)
                {
                    stack2.pop();
                    System.out.print(stack1.pop().element + "   ");
                }
    
                if(!stack1.empty())
                {
                    stack2.pop();
                    stack2.push(1);
                    Node = stack1.peek();
                    Node = Node.right;
                }
            }
        }
    
        /*
         * 层序遍历
         * 非递归
         */
        public void levelOrder1(BinaryNode<AnyType> Node) {
            if (Node == null) {
                return;
            }
    
            BinaryNode<AnyType> binaryNode;
            Queue<BinaryNode> queue = new LinkedList<>();
            queue.add(Node);
    
            while (queue.size() != 0) {
                binaryNode = queue.poll();
    
                System.out.print(binaryNode.element + "  ");
    
                if (binaryNode.left != null) {
                    queue.offer(binaryNode.left);
                }
                if (binaryNode.right != null) {
                    queue.offer(binaryNode.right);
                }
            }
        }
    
        public static void main( String[] args )
        {
            int[] input = {4, 2, 6, 1, 3, 5, 7, 8, 10};
            Tree<Integer> tree = new Tree<>();
            for(int i = 0; i < input.length; i++)
            {
                tree.insert(input[i]);
            }
            System.out.print("递归前序遍历 :");
            tree.preOrder(tree.root);
            System.out.print("
    非递归前序遍历:");
            tree.preOrder1(tree.root);
            System.out.print("
    递归中序遍历 :");
            tree.midOrder(tree.root);
            System.out.print("
    非递归中序遍历 :");
            tree.midOrder1(tree.root);
            System.out.print("
    递归后序遍历 :");
            tree.posOrder(tree.root);
            System.out.print("
    非递归后序遍历 :");
            tree.posOrder1(tree.root);
            System.out.print("
    递归层序遍历:");
            tree.levelOrder(tree.root);
            System.out.print("
    非递归层序遍历 :");
            tree.levelOrder1(tree.root);
        }
    }
    

      在以上代码中,preOrder1、midOrder1、posOrder1、levelOrder1四个函数,分别代表了非递归实现的二叉树前序、中序、后序、层序遍历遍历。

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  • 原文地址:https://www.cnblogs.com/liuyang0/p/6271331.html
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