HeHe
Time Limit: 5000/3000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 350 Accepted Submission(s): 148
Problem Description
M
You are expected to write a program to point out some elements of M.
Input
Multi test cases (about 100), every case occupies two lines.
The first line contains an integer n.
Then second line contain 2*n-1 integers t0,t1,t2,t3,…,t2∗n−4,t2∗n−3,t2∗n−2 separated by exact one space.
The third line contains an integer m, indicates the number of query.
Next m lines will give queries
r0r1r2⋮rm−1c0c1c2⋮cm−1
For r0,c0 the program will query the element of M which locates in the rth0 row, cth0 column. For ri,ci(0<i<m), assume that the answer of i−1th query is ANS, the program will query the element of M which locates in ((ri+AN row, ((ci+AN column.
Please process to the end of file.
[Technical Specification]
1≤n≤1000
0≤ti≤100
0≤ri,ci≤n−1
1≤m≤100000
The first line contains an integer n.
Then second line contain 2*n-1 integers t0,t1,t2,t3,…,t2∗n−4,t2∗n−3,t2∗n−2 separated by exact one space.
The third line contains an integer m, indicates the number of query.
Next m lines will give queries
r0r1r2⋮rm−1c0c1c2⋮cm−1
For r0,c0 the program will query the element of M which locates in the rth0 row, cth0 column. For ri,ci(0<i<m), assume that the answer of i−1th query is ANS, the program will query the element of M which locates in ((ri+AN row, ((ci+AN column.
Please process to the end of file.
[Technical Specification]
1≤n≤1000
0≤ti≤100
0≤ri,ci≤n−1
1≤m≤100000
Output
For each case,output the sum of the answer of each query.
Sample Input
3
1 2 3 1 2
2
0 0
1 2
4
10 5 7 2 10 5 7
3
1 2
3 0
2 1
2
1 2 3
4
0 0
0 1
1 0
1 1
Sample Output
23
348
22
Hint
$quad ext{For the first case }M = egin{pmatrix}
3 & 1 & 2\
2 & 3 & 1\
1 & 2 & 3
end{pmatrix}$
$ ext{For the second case }M = egin{pmatrix}
2 & 10 & 5 & 7\
7 & 2 & 10 & 5\
5 & 7 & 2 & 10\
10 & 5 & 7 & 2
end{pmatrix}$Source
这题很卡时间,所以我们不能赋值给二维矩阵再去操作,应该直接在 t 数组上面操作,a[i][j] 与 t[n-1+j-i] 一一对应,所以我们求解矩阵上某个值时直接用 t 数组操作好了。还有就是答案会超出整形表示范围,开_int64.
#include <iostream> #include <stdio.h> #include <math.h> #include <stdlib.h> #include <algorithm> #include <string.h> using namespace std; const int N = 2005; int v[N]; int n; int main() { while(scanf("%d",&n)!=EOF){ for(int i=0;i<=2*n-2;i++){ scanf("%d",&v[i]); } int q; int temp=0; long long ans = 0; scanf("%d",&q); while(q--){ int r,c; scanf("%d%d",&r,&c); r = (r+temp)%n,c = (c+temp)%n; temp = 0; for(int i=0;i<n;i++){ temp+= v[n-1+i-r]*v[n-1+c-i]; } ans += temp; } printf("%lld ",ans); } return 0; }