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  • 复制对象 copy 与mutable copy

     

    通过copy方法可以创建可变对象或不可变对象的不可变副本,对于不可变副本,其对象的值不可以改变。

    通过mutableCopy方法可以创建可变对象或不可变对象的可变副本,对于可变副本其对象是可变的。  

    复制分为浅复制和深复制两种:浅复制只是复制对象的引用,并没有复制对象的具体内容。深复制则创建了要复制对象的具体内容,并返回对象副本的引用。

    对于复制Foundation中的对象,默认并不是深复制,例如copy NSMutableArray对象是浅复制,只是对其引用进行复制;而copy NSMutableString对象是深复制,对原来引用的对象的具体内容也进行了复制。

    1.NSMutableArray和NSArray

    首先创建1个数组(该数组中有3个对象)和4个数组指针:

    NSMutableArray *marray1 = [NSMutableArray arrayWithObjects:
                                       [NSMutableString stringWithString:@"1"],
                                       [NSMutableString stringWithString:@"2"],
                                       [NSMutableString stringWithFormat:@"3"],
                                       nil];
            NSMutableArray *marray2 = [marray1 mutableCopy];
            NSArray *array1 = [marray1 copy];
            NSArray *array2 = [marray1 mutableCopy];

    (1)添加字符串到marray1[0]中:

    // append string to marray1[0]
            NSMutableString *mstr = marray1[0];
            [mstr appendString:@" append"];
            NSLog(@"append string to marray1[0]");
            NSLog(@"marray1 = %@", marray1);
            NSLog(@"marray2 = %@", marray2);
            NSLog(@"array1 = %@", array1);
            NSLog(@"array2 = %@", array2);
    2014-01-31 21:10:39.097 Array[298:303] append string to marray1[0]
    2014-01-31 21:10:39.098 Array[298:303] marray1 = (
        "1 append",
        2,
        3
    )
    2014-01-31 21:10:39.098 Array[298:303] marray2 = (
        "1 append",
        2,
        3
    )
    2014-01-31 21:10:39.098 Array[298:303] array1 = (
        "1 append",
        2,
        3
    )
    2014-01-31 21:10:39.099 Array[298:303] array2 = (
        "1 append",
        2,
        3
    )

    分析:

    假设marray1中保存的是obj1,obj2,obj3组成的数组的首地址。将marray1复制给marray2,array1和array2,只是将指向数组第一个对象的内存地址复制到marray2等数组指针中保存。

    在marray1[0]指向的对象obj1后面附加字符串append,由于marray1,marray2,array1和array2第一个指针指向的对象都是obj1,所以输出一致。

    这里的copy方法和简单的赋值作用是一致的。

    (2)为marray1[0]设置新的对象值:(注意(2)、(3)和(1)是相互独立的,下同)

    // set new object to marray1[0]
            marray1[0] = [NSMutableString stringWithString:@"new 1"];
            NSLog(@"set new object to marray1[0]");
            NSLog(@"marray1 = %@", marray1);
            NSLog(@"marray2 = %@", marray2);
            NSLog(@"array1 = %@", array1);
            NSLog(@"array2 = %@", array2);
    2014-01-31 20:50:52.003 Array[4151:303] set new object to marray1[0]
    2014-01-31 20:50:52.004 Array[4151:303] marray1 = (
        "new 1",
        2,
        3
    )
    2014-01-31 20:50:52.005 Array[4151:303] marray2 = (
        1,
        2,
        3
    )
    2014-01-31 20:50:52.005 Array[4151:303] array1 = (
        1,
        2,
        3
    )
    2014-01-31 20:50:52.005 Array[4151:303] array2 = (
        1,
        2,
        3
    )

    分析:

    这里创建了一个新的NSMutableString对象将其引用赋给marray1[0],而其他数组指针指向的对象不变,所以输出时其他数组不受影响。

    (3)添加新的对象到marray1中:

    // add new object to marray1
            [marray1 addObject:[NSMutableString stringWithString:@"4"]];
            NSLog(@"add new object to marray1");
            NSLog(@"marray1 = %@", marray1);
            NSLog(@"marray2 = %@", marray2);
            NSLog(@"array1 = %@", array1);
            NSLog(@"array2 = %@", array2);
    2014-01-31 20:51:46.867 Array[4167:303] add new object to marray1
    2014-01-31 20:51:46.869 Array[4167:303] marray1 = (
        1,
        2,
        3,
        4
    )
    2014-01-31 20:51:46.869 Array[4167:303] marray2 = (
        1,
        2,
        3
    )
    2014-01-31 20:51:46.869 Array[4167:303] array1 = (
        1,
        2,
        3
    )
    2014-01-31 20:51:46.869 Array[4167:303] array2 = (
        1,
        2,
        3
    )

    分析:

    这里创建了一个新的可变字符串对象,并将其内存地址保存到指针marray1[3]中。而其他几个数组指针的引用不受影响。

    (4)操作数组的引用

    如果要单独替换marray1[0]指向的对象,应该先创建一个对象,然后再替换marray1[0]的引用。这样就不会对marray2[0]指向的对象造成影响。

    NSMutableArray *marray1 = [NSMutableArray arrayWithObjects:
                                       [NSMutableString stringWithString:@"1"],
                                       [NSMutableString stringWithString:@"2"],
                                       [NSMutableString stringWithFormat:@"3"],
                                       nil];
            NSMutableArray *marray2 = [marray1 mutableCopy];
            NSArray *array1 = [marray1 copy];
            NSArray *array2 = [marray1 mutableCopy];
            NSMutableString *mstr = [NSMutableString stringWithString:marray1[0]]; // 创建新的对象
            [mstr appendString:@" append"];
            [marray1 replaceObjectAtIndex:0 withObject:mstr]; // 替换marray1[0]的引用
            
            NSLog(@"marray1 = %@", marray1);
            NSLog(@"marray2 = %@", marray2);
            NSLog(@"array1 = %@", array1);
            NSLog(@"array2 = %@", array2);

    控制台输出:

    2014-01-31 20:09:33.678 Dictionary[3735:303] marray1 = (
        "1 append",
        2,
        3
    )
    2014-01-31 20:09:33.679 Dictionary[3735:303] marray2 = (
        1,
        2,
        3
    )
    2014-01-31 20:09:33.680 Dictionary[3735:303] array1 = (
        1,
        2,
        3
    )
    2014-01-31 20:09:33.680 Dictionary[3735:303] array2 = (
        1,
        2,
        3
    )

    再看一个例子:

    NSMutableArray *marray1 = [NSMutableArray arrayWithObjects:
                                       [NSMutableString stringWithString:@"1"],
                                       [NSMutableString stringWithString:@"2"],
                                       [NSMutableString stringWithFormat:@"3"],
                                       nil];
            NSMutableArray *marray2 = [marray1 mutableCopy];
            NSArray *array1 = [marray1 copy];
            NSArray *array2 = [marray1 mutableCopy];
            
            [marray1 removeObjectAtIndex:0];
            
            NSLog(@"marray1 = %@", marray1);
            NSLog(@"marray2 = %@", marray2);
            NSLog(@"array1 = %@", array1);
            NSLog(@"array2 = %@", array2);

    控制台输出:

    2014-01-31 20:10:40.716 Dictionary[3746:303] marray1 = (
        2,
        3
    )
    2014-01-31 20:10:40.717 Dictionary[3746:303] marray2 = (
        1,
        2,
        3
    )
    2014-01-31 20:10:40.717 Dictionary[3746:303] array1 = (
        1,
        2,
        3
    )
    2014-01-31 20:10:40.718 Dictionary[3746:303] array2 = (
        1,
        2,
        3
    )
    尽管marray1,marray2,array1,array2指向同一个数组对象,但是[marray1 removeObjectAtIndex:0]移除的是marray1第一个元素,即移除的是对对象的引用,而不是移除数组中的第一个对象。所以不会影响到marray2  ,array1,array2 。 

    2.NSMutableString和NSString

    复制NSMutableString对象测试代码如下:

    NSMutableString *mstr1 = [NSMutableString stringWithString:@"1"];
            NSMutableString *mstr2 = [mstr1 mutableCopy];
            NSString *str1 = [mstr1 copy];
            NSString *str2 = [mstr1 mutableCopy];
            
            [mstr1 appendString:@" append"];
            NSLog(@"mstr1 = %@", mstr1);
            NSLog(@"mstr2 = %@", mstr2);
            NSLog(@"str1 = %@", str1);
            NSLog(@"str2 = %@", str2);
    2014-01-31 20:54:20.423 String[4221:303] mstr1 = 1 append
    2014-01-31 20:54:20.424 String[4221:303] mstr2 = 1
    2014-01-31 20:54:20.424 String[4221:303] str1 = 1
    2014-01-31 20:54:20.424 String[4221:303] str2 = 1

    分析:

    对mstr1指向的对象STRING1进行复制,这里复制的是对象  STRING1 本身的内容,也就是mstr2,str1,str2将分别指向对象  STRING2,STRING3,STRING4,对STRING1的修改(在后面附加字符串),将不会影响到其他几个引用指向的对象。

    可见这里进行的是深复制。

    注意不要改变copy后的对象的值,因为copy生成的对象是不可变的,强行修改会导致程序崩溃。

    控制台输出为:

    2014-02-01 00:57:24.903 Array[792:303] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Attempt to mutate immutable object with appendString:'

    3.NSMutableDictionary和NSDictionary

    首先创建1个字典(字典中对应3个对象)和4个字典指针:

    NSMutableString *obj1 = [NSMutableString stringWithString:@"obj1"];
            NSMutableString *obj2 = [NSMutableString stringWithString:@"obj2"];
            NSMutableString *obj3 = [NSMutableString stringWithString:@"obj3"];
            NSMutableDictionary *mdic1 = [NSMutableDictionary dictionaryWithObjects:@[obj1, obj2, obj3]
                                                                            forKeys:@[@"key1", @"key2", @"key3"]];
            NSMutableDictionary *mdic2 = [mdic1 mutableCopy];
            NSDictionary *dic1 = [mdic1 copy];
            NSDictionary *dic2 = [mdic1 copy];

    假设指针mdic1的索引key1,key2,key3分别对应对象obj1,obj2,obj3的内存地址。

    对字典进行复制也是浅复制。

    对mdic1复制,并赋值给mdic2,dic1,dic2,那么mdic2,dic1,dic2中指向的是同一个字典。

    (1)添加字符串到mdic1的key1对应的可变字符串对象后:

    // append string to mdic1[@"key1"]
            NSMutableString *mstr = mdic1[@"key1"];
            [mstr appendString:@" append"];
            NSLog(@"append string to midc1[@"key1"]");
            NSLog(@"mdic1 = %@", mdic1);
            NSLog(@"mdic2 = %@", mdic2);
            NSLog(@"dic1 = %@", dic1);
            NSLog(@"dic2 = %@", dic2);
    2014-01-31 22:07:29.241 Dictionary[431:303] append string to midc1[@"key1"]
    2014-01-31 22:07:29.242 Dictionary[431:303] mdic1 = {
        key1 = "obj1 append";
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:07:29.243 Dictionary[431:303] mdic2 = {
        key1 = "obj1 append";
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:07:29.243 Dictionary[431:303] dic1 = {
        key1 = "obj1 append";
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:07:29.243 Dictionary[431:303] dic2 = {
        key1 = "obj1 append";
        key2 = obj2;
        key3 = obj3;
    }

    上面代码中对key1对应的对象obj1进行修改(在对象后面附加字符串),由于mdic2等指向同一个字典,所以其输出将会和mdic1的输出一致。

    (2)设置新的对象给key1:

    // set new object for  key1
            NSMutableString *nobj1 = [NSMutableString stringWithString:@"new obj1"];
            [mdic1 setObject:nobj1 forKey:@"key1"];
            NSLog(@"set new object for key");
            NSLog(@"mdic1 = %@", mdic1);
            NSLog(@"mdic2 = %@", mdic2);
            NSLog(@"dic1 = %@", dic1);
            NSLog(@"dic2 = %@", dic2);
    2014-01-31 22:08:01.617 Dictionary[448:303] set new object for key
    2014-01-31 22:08:01.618 Dictionary[448:303] mdic1 = {
        key1 = "new obj1";
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:08:01.619 Dictionary[448:303] mdic2 = {
        key1 = obj1;
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:08:01.619 Dictionary[448:303] dic1 = {
        key1 = obj1;
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:08:01.619 Dictionary[448:303] dic2 = {
        key1 = obj1;
        key2 = obj2;
        key3 = obj3;
    }

    这里只是修改了mdic1的索引key1中保存的内存地址,并不会对其他引用所指向的对象造成影响。

    (3)在字典中添加新的key-value对:

    // add new key-value
            NSMutableString *obj4 = [NSMutableString stringWithString:@"obj4"];
            [mdic1 setObject:obj4 forKey:@"key4"];
            NSLog(@"add new key-value");
            NSLog(@"mdic1 = %@", mdic1);
            NSLog(@"mdic2 = %@", mdic2);
            NSLog(@"dic1 = %@", dic1);
            NSLog(@"dic2 = %@", dic2);
    2014-01-31 22:12:14.678 Dictionary[466:303] add new key-value
    2014-01-31 22:12:14.679 Dictionary[466:303] mdic1 = {
        key1 = obj1;
        key2 = obj2;
        key3 = obj3;
        key4 = obj4;
    }
    2014-01-31 22:12:14.679 Dictionary[466:303] mdic2 = {
        key1 = obj1;
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:12:14.679 Dictionary[466:303] dic1 = {
        key1 = obj1;
        key2 = obj2;
        key3 = obj3;
    }
    2014-01-31 22:12:14.680 Dictionary[466:303] dic2 = {
        key1 = obj1;
        key2 = obj2;
        key3 = obj3;
    }

    现在为mdic1对应的字典添加新的key-value对,这不会影响到其他字典指针,所以输出不受影响。

    小结:

    1.浅复制复制的是对象的引用,对指针的修改并不会影响到指向的对象,更不会影响到其他指针。 深复制复制的是对象的内容,对对象的操作修改将影响到所有指向该对象的引用。

    2.NSMutableArray和NSMutableDictionary的复制是浅复制,NSMutableString的复制是深复制。由于数组或字典中对象数目或大小可能非常大,所以对对象的复制可能引起大量开销,因此这里只复制引用可以节省开销。

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  • 原文地址:https://www.cnblogs.com/lizhitai/p/4567156.html
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