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  • js小方法,获取知道公历生日 (‘1992-01-19’),获取阴历生日日期,属相,非简单根据年份判断-----------声明:整理自网络!!

     1 let lunar = {
     2   tg: '甲乙丙丁戊己庚辛壬癸',
     3   dz: '子丑寅卯辰巳午未申酉戌亥',
     4   number: '一二三四五六七八九十',
     5   year: '鼠牛虎兔龙蛇马羊猴鸡狗猪',
     6   month: '正二三四五六七八九十冬腊',
     7   monthadd: [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334],
     8   calendar: [0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95],
     9 };
    10 // 获取阴历日期
    11 const getLunarDate = (date) => {
    12   let useDate = new Date();
    13   let year,
    14     month,
    15     day;
    16   if (!date) {
    17     date = new Date(), year = date.getFullYear(), month = date.getMonth(), day = date.getDate();
    18   } else {
    19     date = date.split('-'), year = parseInt(date[0]), month = date[1] - 1, day = parseInt(date[2]);
    20   }
    21 
    22   if (year < 1921 || year > 2020) {
    23     return {};
    24   }
    25 
    26   let total,
    27     m,
    28     n,
    29     k,
    30     bit,
    31     lunarYear,
    32     lunarMonth,
    33     lunarDay;
    34   let isEnd = false;
    35   let tmp = year;
    36   if (tmp < 1900) {
    37     tmp += 1900;
    38   }
    39   total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + lunar.monthadd[month] + day - 38;
    40   if (year % 4 == 0 && month > 1) {
    41     total++;
    42   }
    43   for (m = 0; ; m++) {
    44     k = (lunar.calendar[m] < 0xfff) ? 11 : 12;
    45     for (n = k; n >= 0; n--) {
    46       bit = (lunar.calendar[m] >> n) & 1;
    47       if (total <= 29 + bit) {
    48         isEnd = true;
    49         break;
    50       }
    51       total = total - 29 - bit;
    52     }
    53     if (isEnd) break;
    54   }
    55   lunarYear = 1921 + m;
    56   lunarMonth = k - n + 1;
    57   lunarDay = total;
    58   if (k == 12) {
    59     if (lunarMonth == Math.floor(lunar.calendar[m] / 0x10000) + 1) {
    60       lunarMonth = 1 - lunarMonth;
    61     }
    62     if (lunarMonth > Math.floor(lunar.calendar[m] / 0x10000) + 1) {
    63       lunarMonth--;
    64     }
    65   }
    66 
    67   return {
    68     lunarYear,
    69     lunarMonth,
    70     lunarDay,
    71   };
    72 };
    73 
    74 // 获取阴历年信息
    75 const getLunarDateString = (lunarDate) => {
    76   if (!lunarDate.lunarDay) return;
    77   let data = {};
    78   let lunarYear = lunarDate.lunarYear;
    79   let lunarMonth = lunarDate.lunarMonth;
    80   let lunarDay = lunarDate.lunarDay;
    81 
    82   data.tg = lunar.tg.charAt((lunarYear - 4) % 10);
    83   data.dz = lunar.dz.charAt((lunarYear - 4) % 12);
    84   data.year = lunar.year.charAt((lunarYear - 4) % 12);
    85   data.month = lunarMonth < 1 ? `(闰)${lunar.month.charAt(-lunarMonth - 1)}` : lunar.month.charAt(lunarMonth - 1);
    86 
    87   data.day = (lunarDay < 11) ? '初' : ((lunarDay < 20) ? '十' : ((lunarDay < 30) ? '廿' : '三十'));
    88   if (lunarDay % 10 != 0 || lunarDay == 10) {
    89     data.day += lunar.number.charAt((lunarDay - 1) % 10);
    90   }
    91 
    92   return data;
    93 };
    94 export default {
    95   getLunarDate,
    96   getLunarDateString,
    97 };

    用法:

    import Zodiac from '../js/shengxiao.js';
    Zodiac.getLunarDate('1992-1-19');   // 返回值 1991-12-15
    Zodiac.getLunarDateString('1991-12-15');  // 返回值
    {
    day: "十五",
    dz: "未",
    month: "腊",
    tg: "辛",
    year: "羊"
     
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  • 原文地址:https://www.cnblogs.com/lml2017/p/10301979.html
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