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  • 【Azure Developer】使用.Net Core解析JSON的笔记

    在C#中解析JSON的一些历史代码记录,分别记录针对各种情况的解析方式。

    DLL的引用

    using Newtonsoft.Json;
    using Newtonsoft.Json.Linq;

    需要使用的类型

    JArray:对应JSON字符串中的[]数组表示

    JArray x = JArray.Parse(jsonresult);
    
    x[0].ToString()

    //或在知晓JSON格式的对象时,可直接反序列化。
    JsonConvert.DeserializeObject<List<T>>(jsonresult);

    JObject:对应JSON字符串中的{"key":"value"}对象键值对

    JObject obj = JObject.Parse(jsoncontent);
    
    obj ["Key Name"].ToString()

    //或在知晓JSON格式的对象时,可直接反序列化。
    JsonConvert.DeserializeObject<T>(jsoncontent);

    JToken:针对JSON中的值为["value1","value2","value3"]的情况使用JToekn解析后,可以直接使用jtoken[i]依次获取value

    JToken jtvalue= JToken.Parse(jsonstring);
    
    jtvalue[0].ToString()

    JSON字符串格式一:

    [
        {
            "tree": [
                {
                    "id": "b661f9c2-28ee-800a-b621-118a6787a8e6",
                    "name": "Automanage Preview",
                    "type": "productname",                
                    "tree": [
                        {
                            "id": "d2067d69-7bb0-9ee4-cdf8-097211d4229a",
                            "tree": [
                                {
                                    "id": "647d2678-3991-b6f2-595c-5215afaaa61a",
                                    "type": "category",
                                    "typeid": "bcc1837c-6364-a038-6359-afaa3b5144b5",                                
                                    "tags": []
                                },
                                {
                                    "id": "cf520d66-1d51-3644-2d60-f26a2ce384c3",
                                    "name": "Can't create",
                                    "type": "category",
                                    "typeid": "5414a0bd-ea3d-77f1-2bed-07800e2c7e32",
                                    "state": "public",
                                    "tags": []
                                },
                                {
                                    "id": "8279780f-d659-5819-0598-f9cca054d8df",
                                    "name": "Error when ",
                                    "type": "category",
                                    "typeid": "6c35e082-3d87-83d4-9fa7-d213a2e998b3",
                                    "state": "public",
                                    "tags": []
                                },

    使用JArray来解析JSON字符串到由JSON Object组成的数组,也可以通过Linq语句来过滤。

    JArray x = JArray.Parse(result);
    var mc21v = x.Children<JObject>().FirstOrDefault(o => o["tree"][0]["name"] != null && o["tree"][0]["name"].ToString() == "filter value");

    通过对象中的tree ->name查找JSON字符串中高亮部分,也是第一级Tree节点下子节点的name来过滤。当获取到mc21v 节点对象后,继续根据是否由数组,是否是对象(由key存在)依次递归来获取JSON中所携带的值。

    //mc21v
    if (mc21v != null && mc21v["tree"] != null && mc21v["tree"][0]["tree"] != null && mc21v["tree"][0]["tree"].Count() > 0)
    {
    var name = mc21v["tree"][0]["name"].ToString();
    var submc21v = mc21v["tree"][0]["tree"];
    
    foreach (var s in submc21v)
     {
     log.LogInformation(name + " / " + s["name"].ToString());
     }
     }

    JSON字符串格式二:

    {
        "table_parameters": [
            {
                "header_names": [
                    "ID",
                    "Name",
                    "Time",
                    ...
                ],
                "table_parameter_result": [
                    [
                        "3125649",
                        "test",
                        "2020-10-23T18:35:52.4121265",
                        .....
                    ],
                    [
                        "123123545",
                        "test again",
                        "2020-10-23T20:27:27.3168876",
                        ...
                    ],
                    [
                        "120100503",

    以上格式为自定义的JSON表格格式,table_parameters节点中包含表头(header_names)和表内容(table_parameter_result),所以在获取值时候,就需要使用到JArrayJToken。

       JObject details = JObject.Parse(sdresult);
    JToken resultTableObj
    = details["table_parameters"][0]; resultTableObj[i].ToString()

    附加一:使用Python读取JSON格式得文件内容并输出

    import os, uuid
    import json
    
    try:
        local_path = "."
        local_file_name = "All My Case.json"
        upload_file_path = os.path.join(local_path, local_file_name)
    
        with open(upload_file_path, "r") as data:   
            #print(data.read()) 
            y = json.loads(data.read())
            print(len(y))
            for c in y:
                print(c[0]+","+c[8]+","+c[36]+","+c[42])        
    
    except Exception as ex:
        print('Exception:')
        print(ex)

    What is JSON?

    • JSON stands for JavaScript Object Notation
    • JSON is a lightweight data-interchange format
    • JSON is "self-describing" and easy to understand
    • JSON is language independent *

    MORE JSON: https://www.w3schools.com/js/js_json_intro.asp

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  • 原文地址:https://www.cnblogs.com/lulight/p/13871409.html
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