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  • 网络流--最大流--hlpp(预流推进)模板

    //500ms 秒掉洛谷推流问题
    #include <algorithm>
    #include <iostream>
    #include <cstring>
    #include <vector>
    #include <queue>
    using namespace std;
    typedef long long LL;
    typedef long long F_type;
    const int MAXN = 1.2e3 + 10, INF = 0x3f3f3f3f;
    const LL LINF = (LL)INF << 32 | INF;
    struct Edge
    {
        int v, rev;
        F_type cap;
        Edge(int a, F_type b, int c) : v(a), rev(c), cap(b) {}
    };
    const F_type maxf=LINF;
    F_type exflow[MAXN];
    int h[MAXN], cnt[MAXN];
    int ht, N, S, T, labelcnt;
    vector<Edge> G[MAXN];
    vector<int> hq[MAXN];
    void clear(int n = MAXN - 1)
    {
        ht = labelcnt = 0;
        for (int i = 0; i <= n; i++)
            G[i].clear();
    }
    void addEdge(int u, int v, F_type cap)
    {
        G[u].emplace_back(v, cap, G[v].size());
        G[v].emplace_back(u, 0, G[u].size() - 1);
    }
    void update(int u, int newh)
    {
        ++labelcnt;
        if (h[u] != N + 1)
            --cnt[h[u]];
        h[u] = newh;
        if (newh == N + 1)
            return;
        ++cnt[ht = newh];
        if (exflow[u] > 0)
            hq[newh].push_back(u);
    }
    void globalRelabel()
    {
        queue<int> q;
        for (int i = 0; i <= N + 1; i++)
            hq[i].clear();
        for (int i = 0; i <= N; i++)
            h[i] = N + 1, cnt[i] = 0;
        q.push(T);
        labelcnt = ht = h[T] = 0;
        while (!q.empty())
        {
            int u = q.front();
            q.pop();
            for (Edge& e : G[u])
            {
                if (h[e.v] == N + 1 && G[e.v][e.rev].cap)
                {
                    update(e.v, h[u] + 1);
                    q.push(e.v);
                }
            }
            ht = h[u];
        }
    }
    void push(int u, Edge& e)
    {
        if (exflow[e.v] == 0)
            hq[h[e.v]].push_back(e.v);
        F_type df = min(exflow[u], e.cap);
        e.cap -= df;
        G[e.v][e.rev].cap += df;
        exflow[u] -= df;
        exflow[e.v] += df;
    }
    void discharge(int u)
    {
        int nxth = N + 1;
        for (Edge& e : G[u])
            if (e.cap)
            {
                if (h[u] == h[e.v] + 1)
                {
                    push(u, e);
                    if (exflow[u] <= 0)
                        return;
                }
                else
                    nxth = min(nxth, h[e.v] + 1);
            }
        if (cnt[h[u]] > 1)
            update(u, nxth);
        else
            for (; ht >= h[u]; hq[ht--].clear())
            {
                for (int& j : hq[ht])
                    update(j, N + 1);
            }
    }
    F_type maxFlow(int s, int t, int n)
    {
        S = s, T = t, N = n;
        memset(exflow, 0, sizeof(exflow));
        exflow[S] = maxf;
        exflow[T] = -maxf;
        globalRelabel();
        for (Edge& e : G[S])
            push(S, e);
        for (; ht >= 0; --ht)
        {
            while (!hq[ht].empty())
            {
                int u = hq[ht].back();
                hq[ht].pop_back();
                discharge(u);
                if (labelcnt > (N << 2))
                    globalRelabel();
            }
        }
        return exflow[T] + maxf;
    }
    
    int main()
    {
        int n, m, s, t, u, v, w;
        scanf("%d%d%d%d", &n, &m, &s, &t);
        while (m--)
        {
            scanf("%d%d%d", &u, &v, &w);
            addEdge(u, v, w);
        }
        printf("%d", maxFlow(s, t, n));
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/lunatic-talent/p/12798636.html
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