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  • 2019HDU多校 Round3

    09 K Subsequence

    #include  <bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    const int INF = 0x3f3f3f3f;
    
    ll mincost;
    int n, m, cnt, s, t, ts;
    struct node {
        int to, nex, val, cost;
    }E[4012005];
    int head[4005];
    int cur[4005];
    
    void addedge(int u, int v, int va, int co) {
        E[++cnt].to = v; E[cnt].nex = head[u]; head[u] = cnt; E[cnt].val = va; E[cnt].cost = co;
        E[++cnt].to = u; E[cnt].nex = head[v]; head[v] = cnt; E[cnt].val = 0; E[cnt].cost = -co;
    }
    
    struct no1 {
        int to, edge;
    }pre[4005];
    
    int dis[4005];
    bool inque[4005];
    int que[4000005];
    bool spfa() {
        for(int i = 1; i <= t; i++) dis[i] = INF, inque[i] = 0, cur[i] = head[i];
        dis[s] = 0; inque[s] = 1;
        int top = 0;
        que[++top] = s;
    
        while(top) {
            int u = que[top];
            top--;
            inque[u] = 0;
    
            for(int i = head[u]; i; i = E[i].nex) {
                int v = E[i].to;
                if(E[i].val && dis[v] > dis[u] + 1LL * E[i].cost) {
                    dis[v] = dis[u] + 1LL * E[i].cost;
                    pre[v].to = u;
                    pre[v].edge = i;
                    if(!inque[v]) {
                        inque[v] = 1;
                        que[++top] = v;
                    }
                }
            }
        }
        return dis[t] != INF;
    }
    
    int ans, cos1;
    void EK() {
        ans = cos1 = 0;
    
        while(spfa()) {
            int mi = INF;
            for(int i = t; i != s; i = pre[i].to) {
                mi = min(mi, E[pre[i].edge].val);
            }
            for(int i = t; i != s; i = pre[i].to) {
                E[pre[i].edge].val -= mi;
                E[pre[i].edge ^ 1].val += mi;
            }
            //for(int i = 1; i <= n; i++) h[i] += dis[i];
            ans += mi;
            cos1 += mi * dis[t];
        }
    }
    
    
    /*
    ll h[4005];
    ll dis[4005];
    bool vvis[4005];
    bool dij() {
        for(int i = 1; i <= t; i++) dis[i] = INF, cur[i] = head[i], vvis[i] = 0;
        dis[s] = 0;
        priority_queue< pair<int, int> > que;
        que.push(make_pair(0, s));
    
        while(!que.empty()) {
            int u = que.top().second;
            que.pop();
    
            if(vvis[u]) continue;
            vvis[u] = 1;
    
            for(int i = head[u]; i; i = E[i].nex) {
                int v = E[i].to;
                if(E[i].val && dis[v] + h[v] > dis[u] + 1LL * E[i].cost + h[u]) {
                    dis[v] = dis[u] + 1LL * E[i].cost + h[u] - h[v];
                    que.push(make_pair(-dis[v], v));
                }
            }
        }
        return dis[t] != INF;
    }*/
    
    
    int q[2005];
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &m);
            cnt = 1;
            memset(head, 0, sizeof(head));
            for(int i = 1; i <= n; i++) scanf("%d", &q[i]);
            s = n * 2 + 1;
            ts = s + 1;
            t = ts + 1;
            for(int i = 1; i <= n; i++) {
                for(int j = i + 1; j <= n; j++) {
                    if(q[i] <= q[j]) addedge(i + n, j, 1, 0);
                }
            }
    
            for(int i = 1; i <= n; i++) addedge(s, i, 1, 0), addedge(i + n, ts, 1, 0), addedge(i, i + n, 1, -q[i]);
            addedge(ts, t, m, 0);
    
            EK();
            printf("%d
    ", -cos1);
        }
        return 0;
    }
    /*
    1
    9 2
    5 3 2 1 4 2 1 4 6
    */
    K Subsequence
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  • 原文地址:https://www.cnblogs.com/lwqq3/p/11278895.html
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