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  • 贝塞尔曲线算法,js贝塞尔曲线路径点

         //anchorpoints:贝塞尔基点
            //pointsAmount:生成的点数
        //return 路径点的Array
    function CreateBezierPoints(anchorpoints, pointsAmount) { var points = []; for (var i = 0; i < pointsAmount; i++) { var point = MultiPointBezier(anchorpoints, i / pointsAmount); points.push(point); } return points; } function MultiPointBezier(points, t) { var len = points.length; var x = 0, y = 0; var erxiangshi = function (start, end) { var cs = 1, bcs = 1; while (end > 0) { cs *= start; bcs *= end; start--; end--; } return (cs / bcs); }; for (var i = 0; i < len; i++) { var point = points[i]; x += point.x * Math.pow((1 - t), (len - 1 - i)) * Math.pow(t, i) * (erxiangshi(len - 1, i)); y += point.y * Math.pow((1 - t), (len - 1 - i)) * Math.pow(t, i) * (erxiangshi(len - 1, i)); } return { x: x, y: y }; }

    以上是计算高阶贝赛尔曲线所有点的方法,

    方法引用了引用公式

    下面是示例代码

    <!DOCTYPE html>
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
        <title></title>
        <script src="Scripts/jquery-1.7.1.min.js"></script>
        <script type="text/javascript">
            var guijipoints = [];
            var index = 0;
            $(document).ready(function () {
                var ps = [{ x: 0, y: 0 }, { x: 100, y: 200 }, { x: 200, y: 10 }, { x: 300, y: 400 }, { x: 400, y: 20 }, { x: 200, y: 500 }, { x: 500, y: 30 }, { x: 700, y: 300 }, { x: 800, y: 800 }, { x: 800, y: 800 }];
                guijipoints = CreateBezierPoints(ps, 1000);
                var moveobj = $("#move_div");
                setInterval(function () {
                    var p = guijipoints[index];
                    console.log(p.x);
                    moveobj.css({ left: p.x, top: p.y });
                    index++;
                    if (index >= guijipoints.length) {
                        index = 0;
                    }
                }, 1000 / 100);
                guijipoints.forEach(function (obj, i) {
                    createDiv(obj.x, obj.y);
                });
            });
    
            function createDiv(x, y) {
                $("body").append('<div style="position: absolute;  2px; height: 2px; left:' + x + 'px;top:' + y + 'px; overflow: hidden; background-color: #FF0000"></div>');
            }
    
            //anchorpoints:贝塞尔基点
            //pointsAmount:生成的点数
            function CreateBezierPoints(anchorpoints, pointsAmount) {
                var points = [];
                for (var i = 0; i < pointsAmount; i++) {
                    var point = MultiPointBezier(anchorpoints, i / pointsAmount);
                    points.push(point);
                }
                return points;
            }
    
            function MultiPointBezier(points, t) {
                var len = points.length;
                var x = 0, y = 0;
                var erxiangshi = function (start, end) {
                    var cs = 1, bcs = 1;
                    while (end > 0) {
                        cs *= start;
                        bcs *= end;
                        start--;
                        end--;
                    }
                    return (cs / bcs);
                };
                for (var i = 0; i < len; i++) {
                    var point = points[i];
                    x += point.x * Math.pow((1 - t), (len - 1 - i)) * Math.pow(t, i) * (erxiangshi(len - 1, i));
                    y += point.y * Math.pow((1 - t), (len - 1 - i)) * Math.pow(t, i) * (erxiangshi(len - 1, i));
                }
                return { x: x, y: y };
            }
    
        </script>
    
    </head>
    
    <body>
        <div id="move_div" style=" position: absolute; left: 0px; top: 0px; height: 10px;  10px; background-color: red; "></div>
    </body>
    </html>

     运行结果图如下:

    一次、二次、三次贝塞尔曲线函数

    function onebsr(t, a1, a2) {
        return a1 + (a2 - a1) * t;
    }
    
    
    function twobsr(t, a1, a2, a3) {
        return ((1 - t) * (1 - t)) * a1 + 2 * t * (1 - t) * a2 + t * t * a3;
    }
    
    
    function threebsr(t, a1, a2, a3, a4) {
        return a1 * (1 - t) * (1 - t) * (1 - t) + 3 * a2 * t * (1 - t) * (1 - t) + 3 * a3 * t * t * (1 - t) + a4 * t * t * t;
    }
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  • 原文地址:https://www.cnblogs.com/lxiang/p/4995255.html
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