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  • $.each遍历json对象

    查看一个简单的jQuery的例子来遍历一个JavaScript数组对象。

    1. var json = [
    2.     {"id":"1","tagName":"apple"},
    3.     {"id":"2","tagName":"orange"},
    4.     {"id":"3","tagName":"banana"},
    5.     {"id":"4","tagName":"watermelon"},
    6.     {"id":"5","tagName":"pineapple"}
    7. ];
    8.    
    9. $.each(json, function(idx, obj) {
    10.     alert(obj.tagName);
    11. });

    上面的代码片断工作正常,提示 "apple", "orange" … 等,如预期一样。

    问题: JSON 字符串

    下面的例子中,声明了一个JSON字符串(随附单或双引号)直接地。

    1. var json = '[{"id":"1","tagName":"apple"},{"id":"2","tagName":"orange"},
    2. {"id":"3","tagName":"banana"},{"id":"4","tagName":"watermelon"},
    3. {"id":"5","tagName":"pineapple"}]';
    4. $.each(json, function(idx, obj) {
    5.     alert(obj.tagName);
    6. });

    在Chrome中,它显示在控制台下面的错误:

    Uncaught TypeError: Cannot use 'in' operator to search for '156' 
    

    in [{"id":"1","tagName":"apple"}...
    			

                
    

    解决方案:JSON字符串转换为JavaScript对象。
    要修复它,通过标准JSON.parse()或jQuery 的 $.parseJSON 将其转换为JavaScript对象。

    1. var json = '[{"id":"1","tagName":"apple"},{"id":"2","tagName":"orange"},
    2. {"id":"3","tagName":"banana"},{"id":"4","tagName":"watermelon"},
    3. {"id":"5","tagName":"pineapple"}]';
    4. $.each(JSON.parse(json), function(idx, obj) {
    5.     alert(obj.tagName);
    6. });
    7. //or
    8. $.each($.parseJSON(json), function(idx, obj) {
    9.     alert(obj.tagName);
    10. });
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  • 原文地址:https://www.cnblogs.com/lxl57610/p/7076862.html
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