zoukankan      html  css  js  c++  java
  • CodeForce 710E

    Generate a String
     

      zscoder wants to generate an input file for some programming competition problem.

    His input is a string consisting of n letters 'a'. He is too lazy to write a generator so he will manually generate the input in a text editor.

    Initially, the text editor is empty. It takes him x seconds to insert or delete a letter 'a' from the text file and y seconds to copy the contents of the entire text file, and duplicate it.

    zscoder wants to find the minimum amount of time needed for him to create the input file of exactly n letters 'a'. Help him to determine the amount of time needed to generate the input.

    Input

      The only line contains three integers n, x and y (1 ≤ n ≤ 107, 1 ≤ x, y ≤ 109) — the number of letters 'a' in the input file and the parameters from the problem statement.

    Output

      Print the only integer t — the minimum amount of time needed to generate the input file.

    Examples
    Input
     
    8 1 1

    Output
     
    4

    Input
     
    8 1 10

    Output
     
    8

    题意:
      给出n(目标字符串有n个‘a’),x(增加或删除一个‘a’需要多少秒),y(复制并粘贴当前的字符串需要多少秒)
    求用最少的时间,生成n个‘a’;
    思路:
      dp题目,当n == 0, 1 时需要时间为0, x
      n为奇数时:可以是 n - 1 加上个‘a’ 或者 n + 1 删除一个‘a’
      n为偶数时:就得看看 复制一半个‘a’需要的时间长,还是一个一个的加的时间长
      
    AC代码:
     1 # include <bits/stdc++.h>
     2 using namespace std;
     3 typedef long long ll;
     4 ll a, b, n;
     5 ll dp(ll i)
     6 {
     7     if(i == 0) 
     8         return 0;
     9     if(i == 1) 
    10         return a;
    11     if(i % 2)
    12     {
    13         ll i1 = dp(i - 1), i2 = dp(i + 1);
    14         return a + min(i1, i2);
    15     }
    16     else if(i / 2 * a <= b)
    17         return i * a;
    18     else 
    19         return b + dp(i / 2);
    20 }
    21 int main()
    22 {
    23     while(~scanf("%I64d", &n))
    24     {
    25         scanf("%I64d%I64d", &a, &b);
    26         printf("%I64d
    ", dp(n));
    27     }
    28     return 0;
    29 }
    View Code
    生命不息,奋斗不止,这才叫青春,青春就是拥有热情相信未来。
  • 相关阅读:
    MySQL++:(转)mybatis 常用 jdbcType数据类型
    CF1556F Sports Betting (状压枚举子集DP)
    ICPC Greater New York Region 2020 F
    post方式实现导出/下载文件
    自定义一个v-if
    在vue项目中引用element-ui时 让el-input 获取焦点的方法
    element-select当下拉框数据过多使用懒加载
    vue强制刷新组件更新数据的方式
    .net core efcore dbfirst(sqlserver,mysql,oracle,postgresql)
    camunda安装配置mysql以及整合springboot
  • 原文地址:https://www.cnblogs.com/lyf-acm/p/5798256.html
Copyright © 2011-2022 走看看