给定一个二叉树,找出其最大深度。
二叉树的深度为根节点到最远叶子节点的最长路径上的节点数。
说明: 叶子节点是指没有子节点的节点。
示例:
给定二叉树 [3,9,20,null,null,15,7]
来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/maximum-depth-of-binary-tree
方法一:递归
# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def maxDepth(self, root: TreeNode) -> int: if not root: return 0 return max(self.maxDepth(root.left),self.maxDepth(root.right))+1
方法二:广度优先搜索(层序遍历)
# Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def maxDepth(self, root: TreeNode) -> int: if not root: return 0 stack=collections.deque([root]) level=0 while stack: size=len(stack) level+=1 for _ in range(size): root=stack.popleft() if root.left: stack.append(root.left) if root.right: stack.append(root.right) return level