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  • NOI2011 兔农

    http://www.lydsy.com/JudgeOnline/problem.php?id=2432

    感觉是day1中最难的一题,还好出题人很良心,给了75分部分分。

    还是跪拜策爷吧~Orz

    http://jcvb.is-programmer.com/posts/39528.html

    代码奇丑。。。。。。

    #include<cstdio>
    #include<cstdlib>
    #include<iostream>
    #include<fstream>
    #include<algorithm>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<queue>
    #include<stack>
    #include<map>
    #include<utility>
    #include<set>
    #include<bitset>
    #include<vector>
    #include<functional>
    #include<deque>
    #include<cctype>
    #include<climits>
    #include<complex>
    //#include<bits/stdc++.h>适用于CF,UOJ,但不适用于poj
     
    using namespace std;
    
    typedef long long LL;
    typedef double DB;
    typedef pair<int,int> PII;
    typedef complex<DB> CP;
    
    #define mmst(a,v) memset(a,v,sizeof(a))
    #define mmcy(a,b) memcpy(a,b,sizeof(a))
    #define re(i,a,b)  for(i=a;i<=b;i++)
    #define red(i,a,b) for(i=a;i>=b;i--)
    #define fi first
    #define se second
    #define m_p(a,b) make_pair(a,b)
    #define SF scanf
    #define PF printf
    #define two(k) (1<<(k))
    
    template<class T>inline T sqr(T x){return x*x;}
    template<class T>inline void upmin(T &t,T tmp){if(t>tmp)t=tmp;}
    template<class T>inline void upmax(T &t,T tmp){if(t<tmp)t=tmp;}
    
    const DB EPS=1e-9;
    inline int sgn(DB x){if(abs(x)<EPS)return 0;return(x>0)?1:-1;}
    const DB Pi=acos(-1.0);
    
    inline int gint()
      {
            int res=0;bool neg=0;char z;
            for(z=getchar();z!=EOF && z!='-' && !isdigit(z);z=getchar());
            if(z==EOF)return 0;
            if(z=='-'){neg=1;z=getchar();}
            for(;z!=EOF && isdigit(z);res=res*10+z-'0',z=getchar());
            return (neg)?-res:res; 
        }
    inline LL gll()
      {
          LL res=0;bool neg=0;char z;
            for(z=getchar();z!=EOF && z!='-' && !isdigit(z);z=getchar());
            if(z==EOF)return 0;
            if(z=='-'){neg=1;z=getchar();}
            for(;z!=EOF && isdigit(z);res=res*10+z-'0',z=getchar());
            return (neg)?-res:res; 
        }
    
    const LL maxK=1000000;
    
    LL N,K,P;
    LL fib[6*maxK+100];
    LL pos[maxK+100];
    LL len[maxK+100],next[maxK+100];
    
    inline LL gcd(LL a,LL b){return b==0 ? a : gcd(b,a%b); }
    inline void extend_gcd(LL a,LL &x,LL b,LL &y)
      {
          if(b==0){x=1;y=0;return;}
          LL dx,dy;
          extend_gcd(b,dx,a%b,dy);
          x=dy;
          y=dx-a/b*dy;
      }
    
    struct Tmatrix
      {
          int n,m;
          LL v[4][4];
          inline void clear(){n=m=0;mmst(v,0);}
          inline friend Tmatrix operator *(Tmatrix a,Tmatrix b)
            {
                int i,j,k;
                Tmatrix c;c.clear();
                c.n=a.n;c.m=b.m;
                re(i,1,c.n)re(j,1,c.m)re(k,1,a.m)c.v[i][j]=(c.v[i][j]+a.v[i][k]*b.v[k][j]%P)%P;
                return c;
            }
      };
    
    Tmatrix A,B;
    
    inline Tmatrix power(Tmatrix a,LL k)
      {
          int i;
          Tmatrix x,y=a;
          x.clear();x.n=x.m=a.n;re(i,1,a.n)x.v[i][i]=1;
          for(;k!=0;k>>=1){if(k&1)x=x*y;y=y*y;}
          return x;
      }
    
    int flag[maxK+100];
    
    int main()
      {
          /*freopen("rabbit.in","r",stdin);
          freopen("rabbit.out","w",stdout);*/
          LL i;
          N=gll();K=gll();P=gll();
          fib[1]=fib[2]=1;
          for(i=3;;i++)
            {
                fib[i]=(fib[i-1]+fib[i-2])%K;
                if(!pos[fib[i]])pos[fib[i]]=i;
                if(fib[i]==1 && fib[i-1]==1)break;
            }
          re(i,1,K-1)
            {
                LL x,y;
              if(gcd(i,K)==1)
                {
                    extend_gcd(i,x,K,y);
                    x=(x%K+K)%K;
                    if(pos[x]==0)
                      {
                        len[i]=-1;
                                    next[i]=-1;
                                }
                    else
                      {
                        len[i]=pos[x];
                        next[i]=i*fib[len[i]-1]%K;
                      }
                }
              else
                len[i]=-1,next[i]=-1;
            }
          A.clear();
          A.n=A.m=3;
          A.v[1][1]=1;A.v[1][2]=1;A.v[1][3]=0;
          A.v[2][1]=1;A.v[2][2]=0;A.v[2][3]=0;
          A.v[3][1]=0;A.v[3][2]=0;A.v[3][3]=1;
          B.clear();
          B.n=B.m=3;
          B.v[1][1]=1;B.v[1][2]=0;B.v[1][3]=-1;
          B.v[2][1]=0;B.v[2][2]=1;B.v[2][3]=0;
          B.v[3][1]=0;B.v[3][2]=0;B.v[3][3]=1;
          
          int p,t;
          for(p=1;!flag[p] && next[p]!=-1;flag[p]=1,p=next[p]);
          if(next[p]!=-1)
            {
                LL lenX=0,lenY=0;Tmatrix X,Y,Z;
                X.clear();X.n=X.m=3;X.v[1][1]=X.v[2][2]=X.v[3][3]=1;
                for(t=1;t!=p;t=next[t])X=B*power(A,len[t])*X,lenX+=len[t];
                if(N>=lenX)
                  {
                          Y.clear();Y.n=Y.m=3;Y.v[1][1]=Y.v[2][2]=Y.v[3][3]=1;
                          for(t=p,Y=B*power(A,len[t])*Y,lenY+=len[t],t=next[t];t!=p;t=next[t])Y=B*power(A,len[t])*Y,lenY+=len[t];
                    Z=power(Y,(N-lenX)/lenY)*X;
                    N=(N-lenX)%lenY;
                    for(t=p;;t=next[t])
                      if(N>=len[t])
                          {
                              Z=B*power(A,len[t])*Z;
                              N-=len[t];
                          }
                        else break;
                      LL y=(Z.v[1][2]+Z.v[1][3])%P,x=(Z.v[2][2]+Z.v[2][3])%P;
                      Y.clear();
                      Y.n=Y.m=2;
                            Y.v[1][1]=1;Y.v[1][2]=1;
                            Y.v[2][1]=1;Y.v[2][2]=0;
                        Z=power(Y,N);
                        LL res=(Z.v[1][1]*y%P+Z.v[1][2]*x%P)%P;
                        cout<<(res%P+P)%P<<endl;
                  }
                else
                  {
                      X.clear();X.n=X.m=3;X.v[1][1]=X.v[2][2]=X.v[3][3]=1;
                      for(t=1;t!=p;t=next[t])
                        if(N>=len[t])
                          {
                              X=B*power(A,len[t])*X;
                              N-=len[t];
                          }
                        else break;
                      LL y=(X.v[1][2]+X.v[1][3])%P,x=(X.v[2][2]+X.v[2][3])%P;
                      Y.clear();
                      Y.n=Y.m=2;
                            Y.v[1][1]=1;Y.v[1][2]=1;
                            Y.v[2][1]=1;Y.v[2][2]=0;
                        Z=power(Y,N);
                        LL res=(Z.v[1][1]*y%P+Z.v[1][2]*x%P)%P;
                        cout<<(res%P+P)%P<<endl;
                  }
            }
          else
            {
                LL lenX=0;Tmatrix X,Y,Z;
                X.clear();X.n=X.m=3;X.v[1][1]=X.v[2][2]=X.v[3][3]=1;
                for(t=1;t!=p;t=next[t])X=B*power(A,len[t])*X,lenX+=len[t];
                if(N>=lenX)
                  {
                          LL y=(X.v[1][2]+X.v[1][3])%P,x=(X.v[2][2]+X.v[2][3])%P;
                    N-=lenX;
                    Y.clear();
                        Y.n=Y.m=2;
                            Y.v[1][1]=1;Y.v[1][2]=1;
                            Y.v[2][1]=1;Y.v[2][2]=0;
                        Z=power(Y,N);
                        LL res=(Z.v[1][1]*y%P+Z.v[1][2]*x%P)%P;
                        cout<<(res%P+P)%P<<endl;
                      }
                    else
                      {
                          X.clear();X.n=X.m=3;X.v[1][1]=X.v[2][2]=X.v[3][3]=1;
                      for(t=1;t!=p;t=next[t])
                        if(N>=len[t])
                          {
                              X=B*power(A,len[t])*X;
                              N-=len[t];
                          }
                        else break;
                      LL y=(X.v[1][2]+X.v[1][3])%P,x=(X.v[2][2]+X.v[2][3])%P;
                      Y.n=Y.m=2;
                            Y.v[1][1]=1;Y.v[1][2]=1;
                            Y.v[2][1]=1;Y.v[2][2]=0;
                        Z=power(Y,N);
                        LL res=(Z.v[1][1]*y%P+Z.v[1][2]*x%P)%P;
                        cout<<(res%P+P)%P<<endl;
                      }
            }
          return 0;
      }
    View Code
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  • 原文地址:https://www.cnblogs.com/maijing/p/4698882.html
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