实时软件控制设计第一次作业

#include <iostream>
#include <string>
#include <stdlib.h> 
#include <math.h>
#include <Eigen/Dense>

#define PN 100//可保存的点的数目 
#define LN 100//可保存线的数目 
#define RN 100//可保存三角形的数目 
#define PI 3.1415926

using namespace Eigen;
using namespace std;

void add ();
void addPoint();
void addLine();
void addRect();
void move();
void rotate();



//模板函数：将string类型变量转换为常用的数值类型（此方法具有普遍适用性）  
template <class Type>  
Type stringToNum(const string& str)  
{  
    istringstream iss(str);  
    Type num;  
    iss >> num;  
    return num;      
}  

class Point {
    
    private :
        Vector2d v;    
        string name;    
    public:
        
        //构造函数
        Point(Vector2d v1){
            v = v1;
        }
        
        Point(Vector2d v1 , string pname) {
            v = v1;
            name = pname;
        } 
        Point() {};
        
        //设置点的x，y坐标 
        void setPoint(Vector2d v1){
            v = v1;
        }
                
        
        Vector2d getPoint() {
            return v;
        }
        
        string getName() {
            return name;
        }
        
        void setName(string pname) {
            name = pname;
        }
};

class Line {
    private :
        Vector2d v1;
        Vector2d v2;
        string name;
        
    public :
        //构造函数
        Line() {};
         
        void setLine(Vector2d vv1,Vector2d vv2) {
            v1 = vv1;
            v2 = vv2;
        }
        
        Vector2d getStartPoint() {
            return v1;
        }
        
        Vector2d getEndPoint() {
            return v2;
        }
        
        void setName(string lname) {
            name = lname;
        }
        
        string getName() {
            return name;
        }
        
        
};

class Rect {
    private :
        Vector2d v1;
        Vector2d v2;
         Vector2d v3;
         string name;
         
    public:
        
        Rect() {};
        
    void setRect(Vector2d vv1,Vector2d vv2,Vector2d vv3) {
        v1 = vv1;
        v2 = vv2;
        v3 = vv3;
    }
    
    Vector2d getPoint1() {
        return v1;
    }
    
    Vector2d getPoint2() {
        return v2;
    }
    
    Vector2d getPoint3() {
        return v3;
    }
    
    void setName(string rname) {
        name = rname;
    }
    
    string getName() {
        return name;
    }
};

string a[5];
int pcnt = 0;
Point point[PN]; 
int lcnt = 0;
Line line[LN];
int rcnt = 0;
Rect rect[RN];


int main(int argc,char *argv[]) {
    
    while(1) {
        string str ; //定义一个字符串去接收命令行传入的值
        getline(cin,str);//接收命令行的字符串 
        
    //将命令行的字符串按空格分割存入a[5]中 
        for(int i=0,j=0;i<str.size();i++) {
            int pos;
            pos = str.find(' ',i);
            if(pos!=std::string::npos) {
                a[j] = str.substr(i,pos-i);
                j++;
                i=pos;
            } else {
                a[j] = str.substr(i,str.size()-i);
                break;
            }
            
         }
         
         if(a[0]=="move") {
             move();
        } else if(a[0]=="rotate") {
            rotate();
        } else {
            add();
        }
    }
    
}

void add() {
    if(a[1]=="1") {
        addPoint();
    } else if(a[1]=="2") {
        addLine();
    } else if(a[1]=="3") {
        addRect();
    } else {
        cout<<"输入格式有误，请按照正确的格式输入！"<<endl;
    }
    
}

void addPoint() {
    Vector2d v;
    string m1,m2; 
    string s = a[2];
    double x,y;
    int pos;
    pos=s.find(',',0);
    if(pos!=std::string::npos) {
        m1 = s.substr(0,pos);
        m2 = s.substr(pos+1,s.size()-pos);
        x = stringToNum<double>(m1);
        y = stringToNum<double>(m2);
     } else {
         cout<<"指令输入有误，要添加点请按照如下结构输入："<<endl;
         cout<<"p1 1 5.2,6.4"<<endl;
         exit(0); 
     }
     v<<x,y;
     
    point[pcnt].setPoint(v);
    point[pcnt].setName(a[0]);
    pcnt++;
    cout<<"添加了一个点:"<<a[0]<<endl;
    cout<<"坐标为:"<<v.transpose()<<endl; 
    
}

void addLine() {
    Vector2d v1,v2;
    string m1,m2,m3,m4;
    string s1 = a[2];
    string s2 = a[3];
    double x1,x2,y1,y2;
    int pos1,pos2;
        pos1=s1.find(',',0);
        
    if(pos1!=std::string::npos) {
        m1 = s1.substr(0,pos1);
        m2 = s1.substr(pos1+1,s1.size()-pos1);
        x1 = stringToNum<double>(m1);
        y1 = stringToNum<double>(m2);
     } else {
         cout<<"指令输入有误，要添加点请按照如下结构输入："<<endl;
         cout<<"l1 2 1,2 3,4"<<endl;
         exit(0); 
    }
    
    pos2=s2.find(',',0);
    if(pos2!=std::string::npos) {
        m3 = s2.substr(0,pos2);
        m4 = s2.substr(pos2+1,s2.size()-pos2);
        x2 = stringToNum<double>(m3);
        y2 = stringToNum<double>(m4);
     } else {
         cout<<"指令输入有误，要添加点请按照如下结构输入："<<endl;
         cout<<"l1 2 1,2 3,4"<<endl;
         exit(0); 
    }
    
    v1<<x1,y1;
    v2<<x2,y2;
    line[lcnt].setLine(v1,v2);
    line[lcnt].setName(a[0]);
    lcnt++;
    cout<<"添加了一条线:"<<a[0]<<endl;
    cout<<"起点坐标为:"<<v1.transpose()<<endl;
    cout<<"终点坐标为:"<<v2.transpose()<<endl; 
}

void addRect() {
    Vector2d v1,v2,v3;
    string m1,m2,m3,m4,m5,m6;
    string s1 = a[2];
    string s2 = a[3];
    string s3 = a[4];
    double x1,x2,x3,y1,y2,y3;
    int pos1,pos2,pos3;
    
    pos1=s1.find(',',0);    
    if(pos1!=std::string::npos) {
        m1 = s1.substr(0,pos1);
        m2 = s1.substr(pos1+1,s1.size()-pos1);
        x1 = stringToNum<double>(m1);
        y1 = stringToNum<double>(m2);
     } else {
         cout<<"指令输入有误，要添加点请按照如下结构输入："<<endl;
         cout<<"l1 2 1,2 3,4 5,6"<<endl;
         exit(0); 
    }
    
    pos2=s2.find(',',0);
    if(pos2!=std::string::npos) {
        m3 = s2.substr(0,pos2);
        m4 = s2.substr(pos2+1,s2.size()-pos2);
        x2 = stringToNum<double>(m3);
        y2 = stringToNum<double>(m4);
     } else {
         cout<<"指令输入有误，要添加点请按照如下结构输入："<<endl;
         cout<<"l1 2 1,2 3,4"<<endl;
         exit(0); 
    }
    
    pos3=s3.find(',',0);
    if(pos3!=std::string::npos) {
        m5 = s3.substr(0,pos3);
        m6 = s3.substr(pos3+1,s3.size()-pos3);
        x3 = stringToNum<double>(m5);
        y3 = stringToNum<double>(m6);
     } else {
         cout<<"指令输入有误，要添加点请按照如下结构输入："<<endl;
         cout<<"l1 2 1,2 3,4 5,6"<<endl;
         exit(0); 
    }
    
    v1<<x1,y1;
    v2<<x2,y2;
    v3<<x3,y3;
    rect[rcnt].setRect(v1,v2,v3);
    rect[rcnt].setName(a[0]);
    rcnt++;
    cout<<"添加了一个三角形:"<<a[0]<<endl;
    cout<<"端点一坐标为："<<v1.transpose()<<endl;
    cout<<"端点二坐标为："<<v2.transpose()<<endl;
    cout<<"端点三坐标为："<<v3.transpose()<<endl;
     
}

void move() {
    string s;
    s = a[1];
    Vector2d v;
    bool find = false;
    string s1 = a[2];
    double x,y;
    int pos;
    string m1,m2;
    
    pos=s1.find(',',0);
    if(pos!=std::string::npos) {
        m1 = s1.substr(0,pos);
        m2 = s1.substr(pos+1,s.size()-pos);
        x = stringToNum<double>(m1);
        y = stringToNum<double>(m2);
     } else {
         cout<<"指令输入有误，要添加点请按照如下结构输入："<<endl;
         cout<<"move XX 2,3"<<endl;
         exit(0); 
     }
     v<<x,y;
    
    for(int i=0;i<PN;i++) {
        if(point[i].getName()==s) {
            find = true;
            Vector2d v1 = point[i].getPoint();
             v1=v1+v;
             cout<<s<<"平移后的点的坐标为:"<<v1.transpose()<<endl;    
        } 
    }
    
    for(int i=0;i<LN;i++) {
        if(line[i].getName()==s) {
            find = true;
            Vector2d v1 = line[i].getStartPoint();
            Vector2d v2 = line[i].getEndPoint();
             v1 = v1+v;
             v2 = v2+v; 
             cout<<"直线"<<s<<"平移后起点的坐标为:"<<v1.transpose()<<endl;
             cout<<"直线"<<s<<"平移后终点的坐标为:"<<v2.transpose()<<endl;    
        } 
    }
    
    for(int i=0;i<RN;i++) {
        if(rect[i].getName()==s) {
            find = true;
            Vector2d v1 = rect[i].getPoint1();
            Vector2d v2 = rect[i].getPoint2();
            Vector2d v3 = rect[i].getPoint3();
             v1 = v1+v;
             v2 = v2+v; 
             v3 = v3+v;
             cout<<"三角形"<<s<<"点1平移后的坐标为:"<<v1.transpose()<<endl;
             cout<<"三角形"<<s<<"点2平移后的坐标为:"<<v2.transpose()<<endl;
             cout<<"三角形"<<s<<"点3平移后的坐标为:"<<v2.transpose()<<endl;    
        } 
    }
    
    if(find==false) {
        cout<<"没有找到对应的点线面，请先添加点线面！"<<endl; 
    }
}

void rotate() {
    string s;
    string s1 = a[2];
    s = a[1];
    MatrixXd rot(2,2);
    bool find = false;
    double deg,avg;
    deg = stringToNum<double>(s1);
    avg = deg*PI/180;
    rot(0,0)=cos(avg);
    rot(0,1)=sin(avg);
    rot(1,0)=-sin(avg);
    rot(1,1)=cos(avg);
   for(int i=0;i<PN;i++) {
        if(point[i].getName()==s) {
            find = true;
            Vector2d v1 = point[i].getPoint();
             v1=rot*v1;
             cout<<"点"<<s<<"绕原点旋转后的坐标为:"<<v1.transpose()<<endl;    
        } 
    }

    for(int i=0;i<LN;i++) {
        if(line[i].getName()==s) {
            find = true;
            Vector2d v1 = line[i].getStartPoint();
            Vector2d v2 = line[i].getEndPoint();
             v1 = rot*v1;
             v2 = rot*v2; 
             cout<<"直线"<<s<<"旋转后起点的坐标为:"<<v1.transpose()<<endl;
             cout<<"直线"<<s<<"旋转后终点的坐标为:"<<v2.transpose()<<endl;    
        } 
    }    
    
        for(int i=0;i<RN;i++) {
        if(rect[i].getName()==s) {
            find = true;
            Vector2d v1 = rect[i].getPoint1();
            Vector2d v2 = rect[i].getPoint2();
            Vector2d v3 = rect[i].getPoint3();
             v1 = rot*v1;
             v2 = rot*v2; 
             v3 = rot*v3;
             cout<<"三角形"<<s<<"点1旋转后的坐标为:"<<v1.transpose()<<endl;
             cout<<"三角形"<<s<<"点2旋转后的坐标为:"<<v2.transpose()<<endl;
             cout<<"三角形"<<s<<"点3旋转后的坐标为:"<<v2.transpose()<<endl;    
        } 
    }
    
    if(find==false) {
        cout<<"没有找到对应的点线面，请先添加点线面！"<<endl;
    } 
}

结果截图：

点线面的创建：

点线面的平移：

点线面的旋转：

输入错误的提示：

解题思路：

1、考虑到程序的可拓展性，所以选择建立了点、线、面类，然后用对象数组来保存点线面的对象（本来应该用容器更好，但是容器的知识不太会）。

2、首先应该将输入字符串拆分，以空格为界限，得到多个子数组用字符串数组保存。

3、保存的字符串要根据其类型进行转换，然后通过if语句判断进入对应的程序段即可

难点：

1、函数和类都应该先定义后使用，这一点和java不一样，所以一开始很不习惯。

2、模版函数

template <class Type>
Type stringToNum(const string& str)
{
istringstream iss(str);
Type num;
iss >> num;
return num;
}

用于字符串向各种基本类型的转换，很实用。

3、这份代码其实冗余度还比较高，需要完善。