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  • 将字符串变成算数式

    import java.math.BigDecimal;
    import java.math.RoundingMode;
    import java.util.*;
    
    import javax.script.ScriptEngine;
    import javax.script.ScriptEngineManager;
    import javax.script.ScriptException;
    import javax.security.auth.kerberos.KerberosKey;
    public class Main{
        private static String multipleBigDecimal(String a,String b)
        {
            double a1=Double.parseDouble(a);
            double b1=Double.parseDouble(b);
            BigDecimal a2=BigDecimal.valueOf(a1);
            BigDecimal b2=BigDecimal.valueOf(b1);
            BigDecimal s=a2.multiply(b2);
            return s.toString();
        }
        private static String divideBigDecimal(String a,String b)
        {
            double a1=Double.parseDouble(a);
            double b1=Double.parseDouble(b);
            BigDecimal a2=BigDecimal.valueOf(a1);
            BigDecimal b2=BigDecimal.valueOf(b1);
            BigDecimal s=a2.divide(b2,5,RoundingMode.HALF_UP);//当这里可能出现无限循环小数时,就必须指定保留位数
            return s.toString();
        }
        private static String addBigDecimal(String a,String b)
        {
            double a1=Double.parseDouble(a);
            double b1=Double.parseDouble(b);
            BigDecimal a2=BigDecimal.valueOf(a1);
            BigDecimal b2=BigDecimal.valueOf(b1);
            BigDecimal s=a2.add(b2);
            return s.toString();
        }
        private static String substractBigDecimal(String a,String b)
        {
            double a1=Double.parseDouble(a);
            double b1=Double.parseDouble(b);
            BigDecimal a2=BigDecimal.valueOf(a1);
            BigDecimal b2=BigDecimal.valueOf(b1);
            BigDecimal s=a2.subtract(b2);
            return s.toString();
        }
        //an example   9+3*3-6/2+3
        private static String sizeyunsuan(String s)
        {
            //1、先将  +-*/找出来
            int p=0;//the count of (+-*/)
            for(int i=0;i<s.length();i++)
            {
                if(s.charAt(i)=='+' || s.charAt(i)=='-' ||s.charAt(i)=='*' ||s.charAt(i)=='/')
                    p++;
            }
            //将字符串按照运算符进行切割总共有  2*p+1个段   example:p=5
            String[] piece=new String[2*p+1];// save pieces divided by operator   11 pieces
            int start=0,index=0;//
            for(int i=0;i<s.length();i++)
            {
                if(s.charAt(i)=='+' || s.charAt(i)=='-' ||s.charAt(i)=='*' ||s.charAt(i)=='/')
                {
                    piece[index]=s.substring(start,i);//index=0  i=1  p[0]="9"
                    index++;
                    piece[index]=""+s.charAt(i);    //index=1  i=1  p[1]="+"
                    index++;
                    start=i+1;   //start=2
                }
            }
            // last piece;
            piece[index]=s.substring(start,s.length());
            ///
            int count=p;
            while(count>0)
            {
                // first calculate */
                for(int i=0;i<piece.length;i++)
                {
                    if(piece[i].equals("*") || piece[i].equals("/"))
                    {
                        //find strs in piece has not calculated
                        //find strs left not equals "p"
                        int l=0;
                        for(l=i-1;l>-1;l--)
                        {
                            if(!piece[l].equals("p"))
                                break;
                        }
                        //find strs right not equals "p"
                        int r=0;
                        for(r=i+1;r<piece.length;r++)
                        {
                            if(!piece[r].equals("p"))
                                break;
                        }
                        if(piece[i].equals("*"))
                        {
                            piece[i]=multipleBigDecimal(piece[l], piece[r]);
                            piece[l]="p";
                            piece[r]="p";
                            count--;
                        }
                        else
                        {
                            piece[i]=divideBigDecimal(piece[l], piece[r]);
                            piece[l]="p";
                            piece[r]="p";
                            count--;
                        }
                        //break;
                    }
                }
                //then calculate +-
                for(int i=0;i<piece.length;i++)
                {
                    if(piece[i].equals("+") || piece[i].equals("-"))
                    {
                        //find strs in piece has not calculated
                        //find strs left not equals "p"
                        int l=0;
                        for(l=i-1;l>-1;l--)
                        {
                            if(!piece[l].equals("p"))
                                break;
                        }
                        //find strs right not equals "p"
                        int r=0;
                        for(r=i+1;r<piece.length;r++)
                        {
                            if(!piece[r].equals("p"))
                                break;
                        }
                        if(piece[i].equals("+"))
                        {
                            piece[i]=addBigDecimal(piece[l], piece[r]);
                            piece[l]="p";
                            piece[r]="p";
                            count--;
                        }
                        else
                        {
                            piece[i]=substractBigDecimal(piece[l], piece[r]);
                            piece[l]="p";
                            piece[r]="p";
                            count--;
                        }
                        //break;
                    }
                }
            }
            String r="";
            //find the string not equals "p"
            for(int i=0;i<piece.length;i++)
            {
                if(!piece[i].equals("p"))
                {
                    r=piece[i];
                    break;
                }
            }
            return r;
        }
        private static void calculate(String s)
        {
            while(true)
            {
                //find the innerest ()
                int start=0,last=0;
                for(int i=0;i<s.length();i++)
                {
                    if(s.charAt(i)=='(')
                        start=i;
                    if(s.charAt(i)==')')
                    {
                        last=i;
                        break;
                    }
                }
                if(last==0)
                {
                    System.out.println("自定义方法"+sizeyunsuan(s));
                    return;
                }
                else
                {
                    String s1=s.substring(0,start);
                    String s2=s.substring(start+1,last);
                    String s3=s.substring(last+1,s.length());
                    s=s1+sizeyunsuan(s2)+s3;
                }
            }
        }
          public static void main(String[] args) throws ScriptException{
              String s="3.6+(1.4+2*32/(3-2.1))*2.3";
              calculate(s);
              
              ScriptEngineManager manager=new ScriptEngineManager();
              ScriptEngine engine=manager.getEngineByName("js");
              Object result=engine.eval(s);
              System.out.println("脚本方法 类型"+result.getClass().getName()+"  值:"+result);
          }
          
    }

    输出

    自定义方法170.375553
    脚本方法 类型java.lang.Double 值:170.37555555555556

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  • 原文地址:https://www.cnblogs.com/maydow/p/4577057.html
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