- 题意:
n*m的一个乘法表,从小到大排序后,输出第k个数
(1 ≤ n, m ≤ 5·105; 1 ≤ k ≤ n·m)
- 分析:
对于k之前的数,排名小于k;k之后的数大于,那么就能够採用二分。
LL n, m, k; LL fun(LL goal) { LL t = 0, ret = 0; while (++t <= m) { ret += min(n, goal / t); } return ret; } LL bin(LL L, LL R, LL goal) { LL M, V; while (L <= R) { M = (L + R) >> 1; V = fun(M); if (V < goal) L = M + 1; else R = M - 1; } return L; } int main() { // freopen("in.txt", "r", stdin); while (cin >> n >> m >> k) { cout << bin(1, 1e15, k) << endl; } return 0; }