zoukankan      html  css  js  c++  java
  • 蓝桥杯 BASIC 27 矩阵乘法(矩阵、二维数组)

    【思路】:注意0次幂是单位矩阵。

    【AC代码】:

    #include <iostream>
    #include <algorithm>
    #include <iomanip>
    #include <cstdio>
    #include <cstring>
    using namespace std;
    
    #define MAX 30+2
    
    void cal(int m[MAX][MAX], int t[MAX][MAX], int r[MAX][MAX], int N)
    {
    	int i = 0, j = 0, k = 0;
    	for (i = 0; i < N; i++)
    	{
    		for (j = 0; j < N; j++)
    		{
    			int temp = 0;
    			for (k = 0; k < N; k++)
    			{
    				temp += m[i][k] * t[k][j];
    			}
    			r[i][j] = temp;
    		}
    	}
    }
    
    void copy(int t[MAX][MAX], int r[MAX][MAX], int N)
    {
    	int i = 0, j = 0;
    	for (i = 0; i < N; i++)
    	{
    		for (j = 0; j < N; j++)
    		{
    			t[i][j] = r[i][j];
    		}
    	} 
    }
    
    int main()
    {
    	//freopen("in.txt", "r", stdin);
    	//freopen("out.txt", "w", stdout);
    	int N = 0, M = 0, matrix[MAX][MAX], temp[MAX][MAX], res[MAX][MAX];
    	int i = 0, j = 0;
    	
    	//input
    	cin >> N >> M;
    	for (i = 0; i < N; i++)
    	{
    		for (j = 0; j < N; j++)
    		{
    			cin >> matrix[i][j];
    			if (i == j)
    			{
    				temp[i][j] = 1;
    				res[i][j] = 1;
    			}
    			else
    			{
    				temp[i][j] = 0;
    				res[i][j] = 0;
    			}
    		}
    	}
    	
    	//cal
    	for (i = 0; i < M; i++)
    	{
    		cal(matrix, temp, res, N);
    		copy(temp, res, N);
    	}
    	
    	for (i = 0; i < N; i++)
    	{
    		for (j = 0; j < N; j++)
    		{
    			cout << res[i][j] << " ";
    		}
    		cout << endl;
    	}
    	return 0;
    }


  • 相关阅读:
    async中series的实现 javascript构件
    6.算法-计数排序
    5.算法-快速排序
    4.堆排序
    3.分治法研究-搜索数组中的最长连续递增子集
    字典树(Trie)学习笔记
    并查集笔记
    求树的遍历
    P1087 FBI树
    P5017 摆渡车
  • 原文地址:https://www.cnblogs.com/mfrbuaa/p/4509229.html
Copyright © 2011-2022 走看看