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  • LeetCode 2 Add Two Numbers

    You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8


    # Definition for singly-linked list.
    # class ListNode
    #     attr_accessor :val, :next
    #     def initialize(val)
    #         @val = val
    #         @next = nil
    #     end
    # end
    
    # @param {ListNode} l1
    # @param {ListNode} l2
    # @return {ListNode}
    def add_two_numbers(l1, l2)
        return l1 if l2.nil?

    return l2 if l1.nil?

    s1 = Array.new s2 = Array.new n = Array.new while l1 s1.unshift(l1.val) l1 = l1.next end while l2 s2.unshift(l2.val) l2 = l2.next end x = s1.join.to_i+s2.join.to_i n = x.to_s.chars.map(&:to_i) ans = ListNode.new(0) d = ans l = n.length() l.times do d.next = ListNode.new(n.pop) d = d.next end ans.next end



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  • 原文地址:https://www.cnblogs.com/mfrbuaa/p/5352947.html
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