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  • SenseTime Ace Coder Challenge 暨 商汤在线编程挑战赛* B. 我觉得海星

    res[i][j]:i->{x1,x2,x3...}->j 的集合的异或值

    c[i][j]:i->{x1,x2,x3...}->j 的集合中元素个数

    flag[i][j][k]:k点是否在i->{x1,x2,x3...}->j 的集合中

    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<algorithm>
    #include<iostream>
    #include<queue>
    #include<map>
    #include<cmath>
    #include<set>
    #include<stack>
    #define ll long long
    #define pb push_back
    #define max(x,y) ((x)>(y)?(x):(y))
    #define min(x,y) ((x)>(y)?(y):(x))
    #define cls(name,x) memset(name,x,sizeof(name))
    #define fs first
    #define sc second
    #define mp make_pair
    #define L(x) (1<<x)
    #define next Next
    #define index Index
    using namespace std;
    const int inf=1e9+10;
    const ll llinf=1e17+10;
    const int maxn=2e2+10;
    const int maxm=1e6+10;
    const int maxk=1e5+10;
    const int mod=1e9+7;
    int n;
    char mapp[maxn][maxn];
    int res[maxn][maxn];
    int c[maxn][maxn];
    bool flag[maxn][maxn][maxn];
    int ans;
    int main()
    {
        //freopen("in.txt","r",stdin);
        int T,cas=1;
        scanf("%d",&T);
        while (T--)
        {
            ans=0;
            scanf("%d",&n);
            cls(c,0);
            cls(flag,0);
            cls(res,0);
            for(int i=0;i<n;i++)
                scanf("%s",mapp[i]);
            for(int i=1;i<=n;i++)
                for(int j=1;j<=n;j++)
                    for(int k=1;k<=n;k++)
                    if(i!=j&&i!=k&&j!=k&&mapp[i-1][k-1]=='1'&&mapp[j-1][k-1]=='1')
                    {
                        flag[i][j][k]=1;
                        res[i][j]^=k;
                        c[i][j]++;
                    }
            for(int i=1;i<=n;i++)
                for(int k1=1;k1<=n;k1++)
                    for(int k2=1;k2<=n;k2++)
                    {
                        if(i==k1||i==k2||k1==k2) continue;
                        if(mapp[k1-1][k2-1]!='1') continue;
    
                        int realres1=res[i][k1],realres2=res[i][k2];
                        int realc1=c[i][k1],realc2=c[i][k2];
                        if(flag[i][k1][k2])
                        {
                            realc1--;
                            realres1^=k2;
                        }
                        if(flag[i][k2][k1])
                        {
                            realc2--;
                            realres2^=k1;
                        }
                        if(realc1>0&&realc2>0)
                        {
                            if(realc1>=2||realc2>=2)
                                ans=1;
                            if(realc1==1&&realc2==1&&(realres1^realres2)!=0)
                                ans=1;
                        }
                    }
            printf("Case #%d: %s
    ",cas++,ans?"Starfish!":"Walk Walk");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/mgz-/p/8848095.html
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