扑克牌算法（2）

核心步骤：利用随机数给数组赋值。

public class wicket_2 {
    public static void main(String[] args) {
        String []s=new String[]{"黑桃","红桃","梅花","方块"};
        String []sign=new String[]{"A","2","3","4","5","6","7","8","9","10","J","Q","K"};
        final int N=52;
        int card[]=new int[N];
        for(int i=0;i<card.length;i++) {
            card[i]+=i;
        }
        System.out.println("开始时牌顺序：");
        for(int i=0;i<card.length;i++) {
            System.out.printf("  %s%s",s[card[i]/13],sign[card[i]%13]);
            if((i+1)%13==0) {
                System.out.println();
            }
        }
        //模拟洗牌
        for(int i=0;i<card.length;i++) {
            card[i]=(int)((Math.random())*52);
        }
        System.out.println("洗牌后的顺序为：");
        for(int i=0;i<card.length;i++) {
            System.out.printf("  %s%s",s[card[i]/13],sign[card[i]%13]);
            if((i+1)%13==0) {
                System.out.println();
            }
        }
    }
}

运算结果：