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  • Climbing Stairs

    You are climbing a stair case. It takes n steps to reach to the top.

    Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

    This problem is actually a Fibonacci problem. The intuition to solve this problem is, the way to N steps stair is the sum of the way to N-1 and N-2 steps stairs.

    • 1, From N - 1 steps to N, there is only one way to take 1 step to get to N
    • 2, From N - 2 steps to N, there is only one way to take a 2 steps to get to N
    • 3, Also, there is no overlapping between the above 2 ways
    • 4, So, the way to get to N steps stair is the sum of N - 1 and N - 2

    Code is Simple 

    public int climbStairs(int n) {
    if (n <= 0) return 0;
    if (n == 1) return 1;
    if (n == 2) return 2;
    int s1 = 1;
    int s2 = 2;
    int result = 0;
    for(int i = 2; i < n; i++){
    result = s1 + s2;
    s1 = s2;
    s2 = result;
    }
    return result;
    }

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  • 原文地址:https://www.cnblogs.com/midan/p/4601374.html
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