zoukankan      html  css  js  c++  java
  • 函数式编程(小练习)

    #文件

    alex,56666,22,Engineer,IT
    rain,456,25,Teacher,Teching


    #实现以下功能
    # 1. 修改个人信息
    # 2. 打印个人信息
    # 3. 修改密码

    choice ='''
    1. 修改个人信息
    2. 打印个人信息
    3. 修改密码
     '''
    def look(accounts,user):
        print('''
        name:%s
        age:  %s
        position:%s
        post:%s'''%(accounts[user][0],accounts[user][2],accounts[user][3],accounts[user][4]))
        output(accounts,user)
    
    def save(accounts_dic):
        f.seek(0)
        f.truncate()
        for k in accounts_dic:
            row = ','.join(accounts_dic[k])
            f.write('%s
    '%row)
        f.flush()
    
    def modify(accounts,user):
        print('''
        %s name:%s
        %s age:  %s
        %s position:%s
        %s post:%s'''%(0,accounts[user][0],2,accounts[user][2],3,accounts[user][3],4,accounts[user][4]))
        number = int(input("请输入修改的序号"))
        change = input((accounts[user][number])+'修改的值')
        accounts[user][number] = change
        print(accounts[user])
        save(accounts)
        output(accounts,user)
    
    
    def passwd(accounts,user):
        print('当前密码为%s'%(accounts[user][1]))
        user_pas = input('请输入新的密码')
        accounts[user][1] = user_pas
        print('新密码为%s'%user_pas)
        save(accounts)
        output(accounts,user)
    
    def output(accounts,user):
        print(choice)
        num = input('请输入数字选项')
        if num == '1':
            modify(accounts,user)
        elif num == '2':
            look(accounts,user)
        elif num == '3':
            passwd(accounts,user)
    
    
    
    
    f_name_new = 'info_new'
    f_new = open(f_name_new,'w+',encoding='utf-8')
    f_name = 'info'
    f = open(f_name,'r+',encoding='utf-8')
    data = f.readlines()
    accounts = {}
    for line in data:
        line = line.strip()
        itmes = line.split(',')
        accounts[itmes[0]] =itmes
    count =0
    while count <3 :
        user = input('User Name>')
        if user in accounts.keys():
            password = input('Password')
            if password == accounts[user][1]:
                print('登陆成功')
                output(accounts,user)
                # print(choice)
                # num = input('请输入数字选项')
                # if num  == '2' :
                #     look(accounts,user)
            else:
                count+=1
                continue
        else:
            count+=1
            continue
    
    f.close()
  • 相关阅读:
    移动端测试知识概览
    24、CSS定位
    23、Xpath
    MySQL触发器
    MySQL存储过程和函数
    Cookie详解
    简单漏桶限流
    PHP异常和错误
    工厂方法模式
    简单工厂模式
  • 原文地址:https://www.cnblogs.com/mjiu/p/8644635.html
Copyright © 2011-2022 走看看