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  • java水题集

    POJ - 1220 进制转换 

     1 import java.io.*;
     2 import java.util.*;
     3 import java.math.*;
     4 
     5 public class Main {
     6     public static int GetNum(char c)
     7     {
     8         if (Character.isDigit(c))return c-'0';
     9         if (Character.isUpperCase(c))return c-'A'+10;
    10         if (Character.isLowerCase(c))return c-'a'+36;
    11         return '0';
    12     }
    13     public static char GetChar(int x)
    14     {
    15         if (x<10)return (char)(x+'0');
    16         else if (x<=35) return (char)(x+'A'-10);
    17         else return (char)(x+'a'-36);
    18     }
    19     public static void main(String[] args) 
    20     {
    21         Scanner cin= new Scanner(new BufferedInputStream(System.in));
    22         int T=cin.nextInt();
    23         while(T--!=0)
    24         {
    25             BigInteger base1=cin.nextBigInteger();
    26             BigInteger base2=cin.nextBigInteger();
    27             BigInteger n=BigInteger.ZERO;
    28             String s=cin.next();
    29             for(int i=0;i<s.length();i++)
    30             {
    31                 char c=s.charAt(i);
    32                 n=n.multiply(base1).add(BigInteger.valueOf(GetNum(c)));
    33             }
    34             String ans=new String();
    35             while(!n.equals(BigInteger.ZERO))
    36             {
    37                 ans=GetChar(n.mod(base2).intValue())+ans;
    38                 n=n.divide(base2);
    39             }
    40             if(ans.length()==0) ans+='0';
    41             System.out.println(base1+" "+s);
    42             System.out.println(base2+" "+ans);
    43             if (T>0)System.out.println();
    44         }
    45 
    46     }
    47 
    48 }
    View Code

     POJ - 1131进制转换

     1 import java.io.*;
     2 import java.math.*;
     3 import java.util.*;
     4 public class Main {
     5 
     6     public static void main(String[] args) 
     7     {
     8         Scanner cin=new Scanner(new BufferedInputStream(System.in));
     9         BigDecimal b= new BigDecimal("8"),k,ans;
    10         String s;
    11         while(cin.hasNext())
    12         {
    13             ans=new BigDecimal(0);
    14             k=new BigDecimal(1);
    15             s=cin.nextLine();
    16             for(int i=2;i<s.length();i++)
    17             {
    18                 k=k.divide(b);
    19                 ans=ans.add( BigDecimal.valueOf(s.charAt(i)-'0').multiply(k));
    20             }
    21             System.out.println(s+" [8] = "+ans.toString()+" [10]");
    22             //System.out.println(s+" [8] = "+ans.toString()+" [10]");
    23         }
    24     }
    25 
    26 }
    View Code

    POJ - 1205 矩阵加速递推

     1 import java.io.*;
     2 import java.math.*;
     3 import java.util.*;
     4 public class Main {
     5     
     6     public static void main(String[] args) 
     7     {
     8         Scanner cin=new Scanner(new BufferedInputStream(System.in));
     9         BigInteger f[]=new BigInteger[1005],Three=BigInteger.valueOf(3);
    10         BigInteger tp[][]=new BigInteger[3][3],a[][]=new BigInteger[3][3];
    11         a[1][1]=Three; a[1][2]=BigInteger.valueOf(-1);
    12         a[2][1]=BigInteger.ONE; a[2][2]=BigInteger.ZERO;
    13         f[0]=BigInteger.ZERO;
    14         f[1]=BigInteger.ONE;
    15         for(int i=2;i<=1000;i++)
    16             f[i]=f[i-1].multiply(Three).subtract(f[i-2]);
    17         while(cin.hasNext())
    18         {
    19             int n=cin.nextInt();
    20             tp=MatrixPower(a,2,n-1);
    21             System.out.println(tp[1][1].toString());
    22         }
    23     }
    24     public static BigInteger[][] MatrixMultiply(BigInteger a[][],BigInteger b[][],int n,int p,int m)
    25     {
    26         BigInteger c[][]=new BigInteger[n+1][m+1];
    27         for(int i=1;i<=n;i++)
    28         for(int j=1;j<=m;j++)
    29             c[i][j]=BigInteger.ZERO;
    30         for(int i=1;i<=n;i++)
    31         for(int j=1;j<=m;j++)    
    32         for(int k=1;k<=p;k++)
    33             c[i][j]=c[i][j].add(a[i][k].multiply(b[k][j]));
    34         return c;
    35     }
    36     public static BigInteger[][] MatrixPower(BigInteger a[][],int n,int p)
    37     {
    38         BigInteger ans[][]=new BigInteger[n+1][n+1];
    39         for(int i=1;i<=n;i++)
    40         for(int j=1;j<=n;j++)
    41             if (i==j)ans[i][j]=BigInteger.ONE;
    42             else ans[i][j]=BigInteger.ZERO;
    43         while(p>0)
    44         {                     
    45             if ((p&1)==1)ans=MatrixMultiply(ans,a,n,n,n);
    46             p=p/2;
    47             a=MatrixMultiply(a,a,n,n,n);
    48         }
    49         return ans;
    50     }
    51 }
    View Code
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  • 原文地址:https://www.cnblogs.com/mmmqqdd/p/10804083.html
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