1,有几位数字
#include<stdio.h>
int main_2_1_digit(){
int n;
while(scanf("%d",&n)){
int count = 0;
if(n==0)
count = 1;
while(n){
count++;
n/=10;
}
printf("%d
",count);
}
return 0;
}
2。三位数的三个数字
#include<stdio.h>
int main_2_2_daffodil(){
int i,j,k;
for(int n=100;n<=999;n++){
i = n % 10;
j = (n/10) % 10;
k = (n/100) % 10;
if( n == i*i*i + j*j*j + k*k*k){
printf("%d
",n);
}
}
return 0;
}
3,韩信点兵
#include<stdio.h>
int main_2_3_hanxin(){
int a,b,c;
int i,sum;
while(scanf("%d%d%d",&a,&b,&c)){
sum = -1;
for(i=10;i<=100;i++){
if(i%3 == a && i%5 == b && i%7 == c){
sum =i;
break;
}
}
if(sum == -1){
printf("No answer
");
}else{
printf("%d
",sum);
}
}
return 0;
}
4。打印倒三角
#include<stdio.h>
int main_2_4_triangle(){
int n;
int i,j;
while(scanf("%d",&n)){
for(i=n;i>0;i--){
for(j=1;j < n;j++){
if(j+i >= n+1){
printf("#");
}else{
printf(" ");
}
}
printf("#");
for(j=n+1;j < 2*n;j++){
if(j-i <= n-1){
printf("#");
}else{
printf(" ");
}
}
printf("
");
}
}
return 0;
}
5,输入n个数,比m小的
#include<stdio.h>
int main_2_5_stat(){
int arr[1000];
int n,m;
int i;
int count;
while(scanf("%d",&n)){
for(i=0;i<n;i++){
scanf("%d",&arr[i]);
}
scanf("%d",&m);
count=0;
for(i=0;i<n;i++){
if(m > arr[i]){
count++;
}
}
printf("%d
",count);
}
return 0;
}
6。数aabb
#include<stdio.h>
#include<math.h>
int main_aabb_complete(){
int a,b,n;
double m;
for(a=1;a<=9;a++){
for(b=0;b<=9;b++){
n=a*1100 + b*11;
m=sqrt((double)n);
//推断m是否为整数
//进行浮点数比較的时候要考虑浮点误差
if(floor(m+0.5) == m){
printf("%d %lf
",n,m);
}
}
}
getchar();
return 0;
}
7,浮点数陷阱
#include<stdio.h>
int main_float_trap(){
double i;
for(i=9;i!=10;i+=0.1){
printf("%.1lf
",i);
if(i>10){
break;
}
}
return 0;
}
8,varble_no_init
#include<stdio.h>
int main_varble_no_init(){
int a,b,c;
printf("%d %d %d",a,b,c);
scanf("%d",&a);
return 0;
}
9,全排列
#include<stdio.h>
int n = 0;
void swap(int *a,int *b){
int m = *a;
*a = *b;
*b = m;
}
void perm(int list[],int k,int m){
int i;
if(k > m){
for(i=0;i<=m;i++){
printf("%d ",list[i]);
}
printf("
");
n++;
}else{
for(i=k;i<=m;i++){
swap(&list[k],&list[i]);
perm(list,k+1,m);
swap(&list[k],&list[i]);
}
}
}
int main_quan_pai_lie_version_1(){
int list[] = {1,2,3,4,5};
perm(list,0,4);
printf("total: %d
",n);
return 0;
}