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  • Geeks : Kruskal’s Minimum Spanning Tree Algorithm 最小生成树

    版权声明:本文作者靖心,靖空间地址:http://blog.csdn.net/kenden23/。未经本作者同意不得转载。

    https://blog.csdn.net/kenden23/article/details/26821635

    寻找图中最小连通的路径,图例如以下:



    算法步骤:

    1. Sort all the edges in non-decreasing order of their weight.
    
    2. Pick the smallest edge. Check if it forms a cycle with the spanning tree 
    formed so far. If cycle is not formed, include this edge. Else, discard it.  
    
    3. Repeat step#2 until there are (V-1) edges in the spanning tree.
    关键是第二步难,这里使用Union Find来解决,能够差点儿小于O(lgn)的时间效率来推断是否须要推断的顶点和已经选择的顶点成环。

    正由于这步,使得原本简单的贪心法。变得不那么简单了。

    这样本算法的时间效率达到:max(O(ElogE) , O(ElogV))

    原文參考:http://www.geeksforgeeks.org/greedy-algorithms-set-2-kruskals-minimum-spanning-tree-mst/

    #pragma once
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    class KruskalsMST
    {
    	struct Edge
    	{
    		int src, des, weight;
    	};
    
    	static int cmp(const void *a, const void *b)
    	{
    		Edge *a1 = (Edge *) a, *b1 = (Edge *) b;
    		return a1->weight - b1->weight;
    	}
    
    	struct Graph
    	{
    		int V, E;
    		Edge *edges;
    		Graph(int v, int e) : V(v), E(e)
    		{
    			edges = new Edge[e];
    		}
    		virtual ~Graph()
    		{
    			if (edges) delete [] edges;
    		}
    	};
    
    	struct SubSet
    	{
    		int parent, rank;
    	};
    
    	int find(SubSet *subs, int i)
    	{
    		if (subs[i].parent != i)
    			subs[i].parent = find(subs, subs[i].parent);
    		return subs[i].parent;
    	}
    
    	void UnionTwo(SubSet *subs, int x, int y)
    	{
    		int xroot = find(subs, x);
    		int yroot = find(subs, y);
    		if (subs[xroot].rank < subs[yroot].rank)
    			subs[xroot].parent = yroot;
    		else if (subs[xroot].rank > subs[yroot].rank)
    			subs[yroot].parent = xroot;
    		else
    		{
    			subs[xroot].rank++;
    			subs[yroot].parent = xroot;
    		}
    	}
    
    	Graph *graph;
    	Edge *res;
    	SubSet *subs;
    
    	void initSubSet()
    	{
    		subs = new SubSet[graph->V];
    		for (int i = 0; i < graph->V; i++)
    		{
    			subs[i].parent = i;
    			subs[i].rank = 0;
    		}
    	}
    
    	void mst()
    	{
    		res = new Edge[graph->V-1];
    
    		qsort(graph->edges, graph->E, sizeof(graph->edges[0]), cmp);
    
    		initSubSet();
    
    		for (int e = 0, i = 0; e < graph->V - 1 && i < graph->E; i++)
    		{
    			Edge nextEdge = graph->edges[i];
    			int x = find(subs, nextEdge.src);
    			int y = find(subs, nextEdge.des);
    			if (x != y)
    			{
    				res[e++] = nextEdge;
    				UnionTwo(subs, x, y);
    			}
    		}
    	}
    
    	void printResult()
    	{
    		printf("Following are the edges in the constructed MST
    ");
    		for (int i = 0; i < graph->V-1; ++i)
    			printf("%d -- %d == %d
    ", res[i].src, res[i].des, res[i].weight);
    	}
    public:
    	KruskalsMST()
    	{
    		/* Let us create following weighted graph
    		10
    		0--------1
    		|       |
    		6|   5   |15
    		|       |
    		2--------3
    		4       */
    		int V = 4;  // Number of vertices in graph
    		int E = 5;  // Number of edges in graph
    		graph = new Graph(V, E);
    
    
    		// add edge 0-1
    		graph->edges[0].src = 0;
    		graph->edges[0].des = 1;
    		graph->edges[0].weight = 10;
    
    		// add edges 0-2
    		graph->edges[1].src = 0;
    		graph->edges[1].des = 2;
    		graph->edges[1].weight = 6;
    
    		// add edges 0-3
    		graph->edges[2].src = 0;
    		graph->edges[2].des = 3;
    		graph->edges[2].weight = 5;
    
    		// add edges 1-3
    		graph->edges[3].src = 1;
    		graph->edges[3].des = 3;
    		graph->edges[3].weight = 15;
    
    		// add edges 2-3
    		graph->edges[4].src = 2;
    		graph->edges[4].des = 3;
    		graph->edges[4].weight = 4;
    
    		mst();
    		printResult();
    	}
    	~KruskalsMST()
    	{
    		if (res) delete [] res;
    		if (subs) delete [] subs;
    		if (graph) delete graph;
    	}
    };



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  • 原文地址:https://www.cnblogs.com/mqxnongmin/p/10542681.html
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