zoukankan      html  css  js  c++  java
  • 1036 Boys vs Girls (25)

    This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

    Input Specification:

    Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.

    Output Specification:

    For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference grade~F~-grade~M~. If one such kind of student is missing, output "Absent" in the corresponding line, and output "NA" in the third line instead.

    Sample Input 1:

    3
    Joe M Math990112 89
    Mike M CS991301 100
    Mary F EE990830 95
    

    Sample Output 1:

    Mary EE990830
    Joe Math990112
    6
    

    Sample Input 2:

    1
    Jean M AA980920 60
    

    Sample Output 2:

    Absent
    Jean AA980920
    NA

     1 #include<iostream>
     2 #include<vector>
     3 #include<algorithm>
     4 using namespace std;
     5 struct node{
     6   char name[11], id[11];
     7   int score;
     8 };
     9 bool cmp(node a, node b){return a.score<b.score;}
    10 int main(){
    11   int n, i;
    12   cin>>n;
    13   vector<node> female, male;
    14   for(i=0; i<n; i++){
    15     node stu;
    16     char sex;
    17     scanf("%s %c %s %d", stu.name, &sex, stu.id, &stu.score);
    18     if(sex=='M') male.push_back(stu);
    19     else female.push_back(stu);
    20   }
    21   sort(male.begin(), male.end(), cmp);
    22   sort(female.begin(), female.end(), cmp);
    23   bool flag = true;
    24   if(female.size()==0) {cout<<"Absent
    "; flag=false;}
    25   else printf("%s %s
    ", female[female.size()-1].name, female[female.size()-1].id);
    26   if(male.size()==0) {cout<<"Absent
    "; flag=false;}
    27   else printf("%s %s
    ", male[0].name, male[0].id);
    28   if(flag) cout<<female[female.size()-1].score-male[0].score<<endl;
    29   else cout<<"NA"<<endl;
    30   return 0;
    31 }
    有疑惑或者更好的解决方法的朋友,可以联系我,大家一起探讨。qq:1546431565
  • 相关阅读:
    如何批量查看容器内部的进程?
    如何一键将k8s中configmap以及secret的配置变成本地环境变量
    如何快速批量下载m3u8(ts)视频?
    如何快速搜索?
    【待学习】知识点/小类
    【待学习】科目/大类
    总览:SpringCloud基础结构
    AES 加密解密
    JVM学习:方法重载的优先级
    反射操作数组---反序列化小知识
  • 原文地址:https://www.cnblogs.com/mr-stn/p/9163688.html
Copyright © 2011-2022 走看看