1050 String Subtraction (20)

Given two strings S~1~ and S~2~, S = S~1~ - S~2~ is defined to be the remaining string after taking all the characters in S~2~ from S~1~. Your task is simply to calculate S~1~ - S~2~ for any given strings. However, it might not be that simple to do it fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives S~1~ and S~2~, respectively. The string lengths of both strings are no more than 10^4^. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print S~1~ - S~2~ in one line.

Sample Input:

They are students.
aeiou

Sample Output:

Thy r stdnts.

注意点：连个字符串都可能包含空格， 要用getline输入

#include<iostream>
#include<vector>
using namespace std;
int main(){
  string s, s1;
  getline(cin, s);
  getline(cin, s1);
  int i;
  vector<int> v(128,-1);
  for(i=0; i<s1.size(); i++) v[s1[i]] = 1;
  for( i=0; i<s.size(); i++)
  if(v[s[i]]!=1) cout<<s[i];
  return 0;
}