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  • PAT 1067 Sort with Swap(0, i)

    Given any permutation of the numbers {0, 1, 2,..., N1}, it is easy to sort them in increasing order. But what if Swap(0, *)is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the following way:

    Swap(0, 1) => {4, 1, 2, 0, 3}
    Swap(0, 3) => {4, 1, 2, 3, 0}
    Swap(0, 4) => {0, 1, 2, 3, 4}
    

    Now you are asked to find the minimum number of swaps need to sort the given permutation of the first N nonnegative integers.

    Input Specification:

    Each input file contains one test case, which gives a positive N (≤) followed by a permutation sequence of {0, 1, ..., N1}. All the numbers in a line are separated by a space.

    Output Specification:

    For each case, simply print in a line the minimum number of swaps need to sort the given permutation.

    Sample Input:

    10
    3 5 7 2 6 4 9 0 8 1
    

    Sample Output:

    9

     1 #include<iostream>
     2 #include<vector>
     3 using namespace std;
     4 int main(){
     5   int n, i, cnt=0, sp=0;
     6   vector<int> v(100000), idx(100000);
     7   scanf("%d", &n);
     8   for(i=0; i<n; i++){
     9     scanf("%d", &v[i]);
    10     idx[v[i]] = i;
    11     if(i==idx[i]) cnt++;
    12   }
    13   int begin=0;
    14   while(cnt<n){
    15     if(idx[0]!=0){
    16       swap(v[idx[0]], v[idx[idx[0]]]);
    17       swap(idx[0], idx[idx[0]]);
    18       cnt++;
    19     }else{
    20       while(v[begin]==begin) begin++;
    21       swap(idx[0], idx[v[begin]]); // 先交换序号再交换值
    22       swap(v[0], v[begin]);
    23     }
    24       sp++;
    25   }
    26   cout<<sp<<endl;;
    27   return 0;
    28 }
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  • 原文地址:https://www.cnblogs.com/mr-stn/p/9574631.html
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