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  • POJ 2074 | 线段相交

    #include<cstdio>
    #include<algorithm>
    #include<cstring>
    #include<cmath>
    #define eps 1e-8
    using namespace std;
    bool dcmp(double x,double y)
    {
        if (fabs(x-y)>eps) return 1;
        return 0;
    }
    struct point
    {
        double x,y;
        point () {};
        point (double _x,double _y)
    	{
    	    x=_x,y=_y;
    	}
        point operator + (const point &a)const
    	{
    	    return point(x+a.x,y+a.y);
    	}
        point operator - (const point &a) const
    	{
    	    return point(x-a.x,y-a.y);
    	}
        double operator * (const point &a)const
    	{
    	    return x*a.y-a.x*y;
    	}
        double dot (const point &a,const point &b)
    	{
    	    return a.x*b.x+a.y*b.y;
    	}
        bool operator < (const point &a)const
    	{
    	    return x<a.x;
    	}
        bool operator == (const point &a)const
    	{
    	    return dcmp(x,a.x) && dcmp(y,a.y);
    	}
    };
    struct range
    {
        double x1,x2,y;
        bool operator < (const range &a)const
    	{
    	    return x1<a.x1;
    	}
    }house,block[1010],road;
    bool cmp(range a,range b)
    {
        return a.x1<b.x1;
    }
    double findinter(point p1,point p2,point p3,point p4){    
        double ans=((p1.x-p3.x)*(p3.y-p4.y)-(p1.y-p3.y)*(p3.x-p4.x))/((p1.x-p2.x)*(p3.y-p4.y)-(p1.y-p2.y)*(p3.x-p4.x));    
       return  p1.x+(p2.x-p1.x)*ans;
    }    
    double getIntersect(point a,point b,point c,point d)
    {
        double A1=b.y-a.y,B1=a.x-b.x,C1=(b.x-a.x)*a.y-(b.y-a.y)*a.x;
        double A2=d.y-c.y,B2=c.x-d.x,C2=(d.x-c.x)*c.y-(d.y-c.y)*c.x;
        return (C2*B1-C1*B2)/(A1*B2-A2*B1);
    }
    int n;
    int main()
    {
    //    freopen("1.out","w",stdout);
        while (scanf("%lf%lf%lf",&house.x1,&house.x2,&house.y)!=0)
        {
    	if (house.x1==0 && house.x2==0 && house.y==0) break;
    	scanf("%lf%lf%lf",&road.x1,&road.x2,&road.y);
    	scanf("%d",&n);
    	for (int i=0;i<n;i++)
    	    scanf("%lf%lf%lf",&block[i].x1,&block[i].x2,&block[i].y);
    	sort(block,block+n,cmp);
    	point p1,p2,p3,p4;
    	p3=point(road.x1,road.y);
    	p4=point(road.x2,road.y);
    	double ans=-1,Lmax=-1.0;
    	for (int i=0;i<=n;i++)
    	{
    	    double l,r;
    	      if (block[i].y>=house.y) continue;
    	    if (i==0)
    		l=road.x1;
    	    else
    	    {
    		p1=point(house.x1,house.y);
    		p2=point(block[i-1].x2,block[i-1].y);
    		l=findinter(p1,p2,p3,p4);
    	    }
    	    if (i==n)
    		r=road.x2;
    	    else
    	    {
    		p1=point(house.x2,house.y);
    		p2=point(block[i].x1,block[i].y);
    		r=findinter(p1,p2,p3,p4);
    	    }
    	    if (l<road.x1) l=road.x1;
    	    if (r>road.x2) r=road.x2;
    	    if (l<Lmax) l=Lmax;
    	    Lmax=max(Lmax,l);
    	    ans=max(ans,r-l);
    	}
    	if (ans<=0) puts("No View");
    	else printf("%.2f
    ",ans);
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/mrsheep/p/8011271.html
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