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  • sql not in 的坑及改写为join

    /*我们接着用上次建的两个表。数据如下*/

    SQL> select * from l;

    STR   V

    ------ -

    left_1 1

    left_2 2

    left_3 3

    left_4 4

    SQL> select * from r;

    STR    V

    ------- -

    right_3 3

    right_4 4

    right_5 5

    right_6 6

    /*如果要返回l表中有而r表为没有的数据(v=1、2),那么用not in写应该如下*/

    SQL> select * from l where v not in(select r.v from r);

    STR   V

    ------ -

    left_1 1

    left_2 2

    /*如果r表中v有空值呢*/

    SQL> insert into r values(null,null);

    1 row inserted

    /*结果集返回错误*/

    SQL> select * from l where v not in(select r.v from r);

    STR   V

    ------ -

    /*这时要增加条件 r.v is not null*/

    SQL> select * from l where v not in(select r.v from r where r.v is not null);

    STR   V

    ------ -

    left_1 1

    left_2 2

    /*not exists语句不受null影响,因为not exists中是等值关系*/

    SQL> select * from l where not exists(selectnull from r where r.v = l.v);

    STR   V

    ------ -

    left_1 1

    left_2 2

    /*以上两种都叫反联接,也可以用join改写解析如下*/

    SQL> select l.*,r.* from l left join ron l.v = r.v order by 2;

    STR   V STR     V

    ------ - ------- -

    left_1 1        

    left_2 2        

    left_3 3 right_3 3

    left_4 4 right_4 4

    /*如上所示,l中有,而r中没有的,就是r.v为空的行,那么加上这个条件后,返回的就是所需数据了*/

    SQL> select l.* from l left join r onl.v = r.v where r.v is null order by 2;

    STR   V

    ------ -

    left_1 1

    left_2 2

    /*如果能前的(+)写法,应该如下,为了便于理解,我们仍分步执行来看*/

    SQL> select left_str,left_v from (selectl.str as left_str,l.v as left_v,r.str as right_str,r.v as right_v from l,rwhere l.v = r.v(+) order by 2);

    LEFT_STR LEFT_V

    -------- ------

    left_1  1

    left_2  2

    left_3  3

    left_4  4

    SQL> select left_str,left_v from (selectl.str as left_str,l.v as left_v,r.str as right_str,r.v as right_v from l,rwhere l.v = r.v(+)) where right_v is null orderby 2;

    LEFT_STR LEFT_V

    -------- ------

    left_1  1

    left_2  2

    /*简化后,语句如下*/

    SQL> select l.* from l,r where l.v =r.v(+) and r.v is null order by 2;

    STR   V

    ------ -

    left_1 1

    left_2 2

    /*有人把这两种弄混了,写为*/

    select l.* from l left join r on (l.v =r.v) and r.v is null order by 2;

    /*那么我们把两个表的数据都返回,看结果*/

    SQL> select l.*,r.* from l left join ron (l.v = r.v) and r.v is null order by 2;

    STR   V STR     V

    ------ - ------- -

    left_1 1        

    left_2 2        

    left_3 3        

    left_4 4        

    /*以上这句整理一下就是*/

    SQL> select l.*,r.* from l left join(select * from r where r.v is null)r on (l.v =r.v) order by 2;

    STR   V STR     V

    ------ - ------- -

    left_1 1        

    left_2 2        

    left_3 3        

    left_4 4

    /*相当于是l与一空行join了*/

    SQL> select * from r where r.v is null;

    STR    V

    ------- -

    SQL>

    /*对join的方法引申一部,改为full join*/

    SQL> select l.*,r.* from l full join ron l.v = r.v order by 2,4;

    STR   V STR     V

    ------ - ------- -

    left_1 1        

    left_2 2        

    left_3 3 right_3 3

    left_4 4 right_4 4

             right_5 5

             right_6 6

    7 rows selected

    SQL>

    /*看上述结果,对别对应l.v为空,与r.v为空就是两个表不匹配的行*/

    SQL> select l.*,r.* from l full join ron l.v = r.v where (l.v is null or r.v is null)order by 2,4;

    STR   V STR     V

    ------ - ------- -

    left_1 1        

    left_2 2        

            right_5 5

            right_6 6

    SQL>

    /*当然,以上语句就不能用(+)改写了*/
    ---------------------

    原文链接:https://blog.csdn.net/jgmydsai/article/details/15810295

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  • 原文地址:https://www.cnblogs.com/mrtiny/p/11320329.html
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