zoukankan      html  css  js  c++  java
  • Dynamic Programming-650. 2 Keys Keyboard

    Initially on a notepad only one character 'A' is present. You can perform two operations on this notepad for each step: 

    1. Copy All: You can copy all the characters present on the notepad (partial copy is not allowed).
    2. Paste: You can paste the characters which are copied last time.

    Given a number n. You have to get exactly n 'A' on the notepad by performing the minimum number of steps permitted. Output the minimum number of steps to get n 'A'. 

    Example 1:

    Input: 3
    Output: 3
    Explanation:
    Intitally, we have one character 'A'.
    In step 1, we use Copy All operation.
    In step 2, we use Paste operation to get 'AA'.
    In step 3, we use Paste operation to get 'AAA'.
    

    Note:

    1. The n will be in the range [1, 1000].
    class Solution {
    public:
        int minSteps(int n) {
            vector<int> dp(n+1,0x7FFFFFFF);
    
            dp[0] = dp[1] = 0;
    
            for(int i=2;i<n+1;++i){
                for(int j=1;j<i;++j){
                    if(i%j==0){
                        dp[i] = min(dp[i], dp[j]+i/j);
                    }
                }
            }
            return dp[n];
        }
    };
  • 相关阅读:
    第九周:关于程序的历史
    第八周
    第八周2
    关于bom和dom的概念及用法应用
    关于css中position的两个属性值sticky和fixed的不同
    css颜色表示法
    atan2(x,y)与pow(x,y)
    第9周作业
    第8周作业
    第⑦周作业
  • 原文地址:https://www.cnblogs.com/msymm/p/8248309.html
Copyright © 2011-2022 走看看