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  • 3555: [Ctsc2014]企鹅QQ 字符串哈希

    枚举每一位即可

    #include<bits/stdc++.h>
    using namespace std;
    int n,l,p;
    long long f1[30005][205],f2[30005][205],mod=10000000000007,bb=13331,ans,sum,tmp[30005];
    char s[30005][205];
    int main()
    {
    	//freopen("xf.in","r",stdin);
    	scanf("%d%d%d",&n,&l,&p);
    	for(int i=1;i<=n;i++)scanf("%s",s[i]+1);
    	for(int i=1;i<=n;i++)
    	{
    		f1[i][1]=s[i][1];
    		for(int j=2;j<=l;j++)f1[i][j]=(f1[i][j-1]*bb+s[i][j])%mod;
    		f2[i][l]=s[i][l];
    		for(int j=l-1;j>=0;j--)f2[i][j]=(f2[i][j+1]*bb+s[i][j])%mod;
    	}
    	for(int i=1;i<=l;i++)
    	{
    		for(int j=1;j<=n;j++)tmp[j]=(f1[j][i-1]*233+f2[j][i+1]*101)%mod;
    		sort(tmp+1,tmp+n+1);
    		for(int j=1;j<=n;j++)if(tmp[j]==tmp[j-1]){sum++;ans+=sum;}else sum=0;
    	}
    	printf("%lld
    ",ans);
    	return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/mybing/p/9082947.html
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