要求:
右侧的可以拖拽
右侧的需要放到正确的对应区可自动吸附
否则释放鼠标回到原位
当所有右侧都放到了对应的左侧
出现成功的画面界面如图:
绿色的三个 实例名称:a0 a1 a2
蓝色的三个 实例名称:b0 b1 b2
代码如下:
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stop();
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var total:Number = 0;
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for (var i:Number = 0; i<3; i++) {
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this["b"+i].id = i;
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//存取编号用于判断是否拖到了目的地
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this["b"+i].x = this["b"+i]._x;
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this["b"+i].y = this["b"+i]._y;
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//注意左面的是x 右面的是 _x
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//.x与.y来存取初始位置,后面的程序
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//在判断没有拖到正确的位置回复位
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this["b"+i].onPress = function() {
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this.startDrag();
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this.hit = false;
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};
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this["b"+i].onRelease = function() {
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this.stopDrag();
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for (var j:Number = 0; j<3; j++) {
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this._parent["a"+j].id = j;
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if (this.hitTest(this._parent["a"+j])) {
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this.crt = this._parent["a"+j].id;
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this.hit = true;
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}
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}
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if (this.crt == this.id && this.hit) {
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//如果碰到了左侧,且位置对了
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this._x = this._parent["a"+this.id]._x;
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this._y = this._parent["a"+this.id]._y;
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//让蓝色的方框的坐标和绿色的一样
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total++;
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//拖动正确的数目 要增加
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} else {
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this._x = this.x;
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this._y = this.y;
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//没有拖动正确复位
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}
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if (total == 3) {
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txt.text = "全部正确";
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}
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};
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}
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naiking
我在醒着