Text Reverse

Text Reverse

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 1027 Accepted Submission(s): 334

Problem Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.

 

Output

For each test case, you should output the text which is processed.

 

Sample Input

3
olleh !dlrow
m'I morf .udh
I ekil .mca

 

Sample Output

hello world!
I'm from hdu.
I like acm.

#include<iostream>
#include <string.h>
#include "stdio.h"
using namespace std;
int main()
{
    int n;
    cin >> n;
    getchar();
    while(n--)
    {
         char a[1001];
         memset(a,0,sizeof(a));
         gets(a);
         char *p ,*q,*k;
         k = q = p = a;

         while(*p!=0)
         {
              int c = 0;
              while(*p == ' ')
              {
                  p++;
                  cout << ' ' ;
              }

              k = p;                    //k标记字母开始的第一个位子
              while(*p!=' ' && *p!=0) //把p移到最后字母的后一个
                 p++;

              q = p;                   //q标记最后一个字符的后一个位子

              p--;                     //倒退一个，p就是标记最后一个字母了，输出全都字母
              while(p>=k)
              {
                   cout << *p;
                   p--;
              }
              p = q;

         }

         cout << endl;
    }

    return 0;
}