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  • MVC中处理Json和JS中处理Json对象

    MVC中处理Json和JS中处理Json对象

    mvc已经很好封装了JSon,不用js那样复杂
    前台:
    <script>
    $.ajax({
    url: "/Home/Test",
    dataType: "json",
    cache: false,
    data: null,
    type: "POST",
    success: function (data) {
    alert(data.Data.Name);
    }
    });

    后台:
    public JsonResult Test()
    {
    JsonResult json = new JsonResult()
    {
    Data = new
    {
    Name = "张三",
    Sex = "男"
    }
    };
    return json;
    }


    前台:
    $.ajax({
    url: "/Home/TestList",
    dataType: "json",
    cache: false,
    data: null,
    type: "POST",
    success: function (data) {
    var msg = "";
    for (var i = 0, length = data.Data.length; i < length; i++) {
    msg += "<DiV>Name:" + data.Data[i].Name + ",Email:" +

    data.Data[i].Email + "</div>";

    }
    $("#msg2").html(msg);
    }
    });

    第二种也可以这样写:
    第二种列表的方法,也可以这样来实现更加简单:

    public JsonResult TestList()
    {
    List<User> userList = new List<User>
    {
    new User{Username="zhangsan",Email="zhangsan@sina.com"},
    new User{Username="Lisi",Email="Lisi@sina.com"}
    };
    return Json(userList);

    //return Json(userList, JsonRequestBehavior.AllowGet);//前台AJAX如果是GET用这句

    }
    $.ajax({
    url: "/Home/TestList",
    dataType: "json",
    cache: false,
    data: null,
    type: "POST",
    success: function (data) {
    var msg = "<table border=1><thead><tr><td>Name</td><td>Email</td>
    </tr></thead><tbody>";
    for (var i = 0, length = data.length; i < length; i++) {
    msg += "<tr><td>" + data[i].Name + "</td><td>"
    + data[i].Email + "</td></tr>";
    }
    msg += "</body></table>";
    $("#msg2").html(msg);
    }
    });
    后台:
    public JsonResult TestList()
    {
    List<User> userList = new List<User>
    {
    new User{Username="zhangsan",Email="zhangsan@sina.com"},
    new User{Username="Lisi",Email="Lisi@sina.com"}
    };
    JsonResult json = new JsonResult()
    {
    Data = userList
    };
    return json;
    }

    另外:使用json比用string返回数据更好

    以前的程序:

    ViewData["msg"] = "{result:true,FileName:"" + new FileInfo(Request.Files[0].FileName).Name +
                      "",FileUrl:"" + fileurl.Replace(""", "") + ""}";
    重构之后的程序:
     JsonResult j = Json(new
                     {
                         Result = true,
                         FileName = new FileInfo(Request.Files[0].FileName).Name,
                         FileUrl = fileurl.Replace(""", "")
                     });
                    ViewData["msg"] = j.Data.ToString();

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  • 原文地址:https://www.cnblogs.com/niuzaihenmang/p/5614430.html
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