Question
Solution
题目大意:
给一个数组排序,这个数组只有0,1,2三个元素,要求只遍历一遍
思路:
记两个索引,lowIdx初始值为0,highIdx初始值为nums.length - 1,遍历数组,如果是2就与highIdx处元素互换且highIdx—,如果是0就与lowIdx处元素互换且lowIdx++,i++,还剩一种情况就是1了,执行i++,循环结束条件是i<=highIdx
Java实现:
public void sortColors(int[] nums) {
int lowIdx = 0;
int highIdx = nums.length - 1;
int i = 0;
while (i <= highIdx) {
if (nums[i] == 2) {
int tmp = nums[highIdx];
nums[highIdx--] = nums[i];
nums[i] = tmp;
} else if (nums[i] == 0) {
int tmp = nums[lowIdx];
nums[lowIdx++] = nums[i];
nums[i++] = tmp;
} else {
i++;
}
}
}