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  • 2019牛客暑期多校训练营(第六场)- Shorten IPv6 Address

    模拟字符串处理

    很暴力的方法,就是把能变成::的全部枚举一次,选最小的即可。。

    #include <bits/stdc++.h>
    #define INF 0x3f3f3f3f
    #define full(a, b) memset(a, b, sizeof a)
    #define __fastIn ios::sync_with_stdio(false), cin.tie(0)
    #define pb push_back
    using namespace std;
    typedef long long LL;
    inline int lowbit(int x){ return x & (-x); }
    inline int read(){
        int ret = 0, w = 0; char ch = 0;
        while(!isdigit(ch)){
            w |= ch == '-', ch = getchar();
        }
        while(isdigit(ch)){
            ret = (ret << 3) + (ret << 1) + (ch ^ 48);
            ch = getchar();
        }
        return w ? -ret : ret;
    }
    inline int lcm(int a, int b){ return a / __gcd(a, b) * b; }
    template <typename A, typename B, typename C>
    inline A fpow(A x, B p, C lyd){
        A ans = 1;
        for(; p; p >>= 1, x = 1LL * x * x % lyd)if(p & 1)ans = 1LL * x * ans % lyd;
        return ans;
    }
    int _;
    const string ch = "0123456789abcdef";
    string s, t;
    
    string calc(string &tmp){
        bool flag = true;
        string ret = "";
        for(int i = 0; i < 4; i ++){
            if(flag && tmp[i] == '0') continue;
            if(tmp[i] != '0') flag = false;
            ret.pb(tmp[i]);
        }
        if(ret.empty()) ret = "0";
        return ret;
    }
    
    string rebuild(string &str){
        int cnt = 0;
        string ret = "";
        for(auto &c: str){
            if(c == ':') cnt ++;
            else cnt = 0;
            if(cnt <= 2) ret.pb(c);
        }
        return ret;
    }
    
    bool cmp(const string &a, const string &b){
        if(a.size() != b.size()) return a.size() < b.size();
        return a < b;
    }
    
    int main(){
    
        //freopen("data.txt", "r", stdin);
        __fastIn;
        int cs = 0;
        for(cin >> _; _; _ --){
            cin >> s;
            t.clear();
            for(int i = 0; i < s.size(); i += 16){
                string str = s.substr(i, 16);
                string tmp = "";
                int st = 0;
                for(int j = 1; j <= 4; j ++){
                    int val = 1, sum = 0;
                    for(int k = st + 3; k >= st; k --){
                        sum += str[k] == '1' ? val : 0;
                        val <<= 1;
                    }
                    st += 4;
                    tmp.pb(ch[sum]);
                }
                tmp = calc(tmp);
                t += tmp, t += ":";
            }
            vector<string> record, ans;
            string cur = "";
            for(int i = 0; i < t.size(); i ++){
                if(t[i] == ':'){
                    record.pb(cur), cur.clear();
                }
                else cur += t[i];
            }
            for(int i = 0; i + 1 < record.size(); i ++){
                if(record[i] == record[i + 1] && record[i] == "0"){
                    int k = 2;
                    while(i + k < record.size() && record[i] == record[i + k]) k ++;
                    k --;
                    string str = "";
                    for(int j = 0; j < record.size(); j ++){
                        if(j == i) str += "::", j += k;
                        else str += record[j];
                        str += ":";
                    }
                    str.pop_back();
                    str = rebuild(str);
                    ans.pb(str);
                }
            }
            cout << "Case #" << ++cs << ": ";
            if(ans.empty()){
                cout << record[0];
                for(int i = 1; i < record.size(); i ++){
                    cout << ":" << record[i];
                }
                cout << endl;
            }
            else{
                cout << min_element(ans.begin(), ans.end(),
                                    [](const string &a, const string &b){
                                        if(a.size() != b.size()) return a.size() < b.size();
                                        return a < b;
                                    })->c_str() << endl;
            }
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/onionQAQ/p/11296163.html
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