php 访问对象的属性（当属性的键名称为数字时）的方法 {}

这篇文章下面写了一个 将 数组转化成对象的方法， 这个数组的键为数字（即数组为索引数组）， 访问对象的时候， $obj->1 显然错位，那到底该怎么样访问对象的数字属性呢？ 

$obj->{1} ; 表示的是访问对象 $obj 的属性的键为 1 对应的属性值！

<?php
/**
 * Created by PhpStorm.
 * User: FLY.YUAN
 * Date: 16-6-14
 * Time: 下午2:26
 */

 function toObject($array)
{
    //$o = (object)'';
    $o = new stdClass();

    foreach ($array as $key => $value) {
        if (is_array($value)) {
            $value = toObject($value);
        }

        $o->$key = $value;
    }

    return $o;
}
$obj = toObject(array( array(1=>23)));
echo "<pre>";
//JSON encode, and then decode your object passing true as the second param in the decode function.
//This will return an associative array.
//var_dump(json_decode(json_encode($obj), true));
var_dump($obj->{0}->{1});

$a = array('123' => '123', '123foo' => '123foo');
$o = json_decode(json_encode($a), true);
var_dump($o);

function recursive_cast_to_array($o) {
    $a = (array)$o;
    foreach ($a as &$value) {
        if (is_object($value)) {
            $value = recursive_cast_to_array($value);
        }
    }

    return $a;
}
$myVar = toObject(array('highlighting' => array('448364' => array('Data' => array(123)))));
$arr = recursive_cast_to_array($myVar);
echo 134;
var_dump( $myVar->highlighting->{448364}->Data->{0});

var_dump(NULL == false);

$test = array();
$test['$.router'] = 123;
var_dump($test);